【发布时间】:2020-03-26 16:14:45
【问题描述】:
我正在尝试添加 JSONSerDe jar 文件以访问 json 数据,将 JSON 数据从 spark 作业加载到 hive 表。我的代码如下所示:
SparkConf sparkConf = new SparkConf().setAppName("KafkaStreamToHbase");
JavaSparkContext sc = new JavaSparkContext(sparkConf);
JavaStreamingContext jssc = new JavaStreamingContext(sc, Durations.seconds(10));
final SQLContext sqlContext = new SQLContext(sc);
final HiveContext hiveContext = new HiveContext(sc);
hiveContext.sql("ADD JAR hdfs://localhost:8020/tmp/hive-serdes-1.0-SNAPSHOT.jar");
hiveContext.sql("LOAD DATA INPATH '/tmp/mar08/part-00000' OVERWRITE INTO TABLE testjson");
但我最终出现以下错误:
java.net.MalformedURLException: unknown protocol: hdfs
at java.net.URL.<init>(URL.java:592)
at java.net.URL.<init>(URL.java:482)
at java.net.URL.<init>(URL.java:431)
at java.net.URI.toURL(URI.java:1096)
at org.apache.spark.sql.hive.client.ClientWrapper.addJar(ClientWrapper.scala:578)
at org.apache.spark.sql.hive.HiveContext.addJar(HiveContext.scala:652)
at org.apache.spark.sql.hive.execution.AddJar.run(commands.scala:89)
at org.apache.spark.sql.execution.ExecutedCommand.sideEffectResult$lzycompute(commands.scala:58)
at org.apache.spark.sql.execution.ExecutedCommand.sideEffectResult(commands.scala:56)
at org.apache.spark.sql.execution.ExecutedCommand.doExecute(commands.scala:70)
at org.apache.spark.sql.execution.SparkPlan$$anonfun$execute$5.apply(SparkPlan.scala:132)
at org.apache.spark.sql.execution.SparkPlan$$anonfun$execute$5.apply(SparkPlan.scala:130)
at org.apache.spark.rdd.RDDOperationScope$.withScope(RDDOperationScope.scala:150)
at org.apache.spark.sql.execution.SparkPlan.execute(SparkPlan.scala:130)
at org.apache.spark.sql.execution.QueryExecution.toRdd$lzycompute(QueryExecution.scala:55)
at org.apache.spark.sql.execution.QueryExecution.toRdd(QueryExecution.scala:55)
at org.apache.spark.sql.DataFrame.<init>(DataFrame.scala:145)
at org.apache.spark.sql.DataFrame.<init>(DataFrame.scala:130)
at org.apache.spark.sql.DataFrame$.apply(DataFrame.scala:52)
at org.apache.spark.sql.SQLContext.sql(SQLContext.scala:817)
at com.macys.apm.kafka.spark.parquet.KafkaStreamToHbase$2.call(KafkaStreamToHbase.java:148)
at com.macys.apm.kafka.spark.parquet.KafkaStreamToHbase$2.call(KafkaStreamToHbase.java:141)
at org.apache.spark.streaming.api.java.JavaDStreamLike$$anonfun$foreachRDD$2.apply(JavaDStreamLike.scala:327)
at org.apache.spark.streaming.api.java.JavaDStreamLike$$anonfun$foreachRDD$2.apply(JavaDStreamLike.scala:327)
at org.apache.spark.streaming.dstream.ForEachDStream$$anonfun$1$$anonfun$apply$mcV$sp$1.apply$mcV$sp(ForEachDStream.scala:50)
at org.apache.spark.streaming.dstream.ForEachDStream$$anonfun$1$$anonfun$apply$mcV$sp$1.apply(ForEachDStream.scala:50)
at org.apache.spark.streaming.dstream.ForEachDStream$$anonfun$1$$anonfun$apply$mcV$sp$1.apply(ForEachDStream.scala:50)
at org.apache.spark.streaming.dstream.DStream.createRDDWithLocalProperties(DStream.scala:426)
at org.apache.spark.streaming.dstream.ForEachDStream$$anonfun$1.apply$mcV$sp(ForEachDStream.scala:49)
at org.apache.spark.streaming.dstream.ForEachDStream$$anonfun$1.apply(ForEachDStream.scala:49)
at org.apache.spark.streaming.dstream.ForEachDStream$$anonfun$1.apply(ForEachDStream.scala:49)
at scala.util.Try$.apply(Try.scala:161)
我能够通过蜂巢壳添加罐子。但是当我尝试在 spark 作业(javacode)中添加使用 hiveContext.sql() 时会引发错误。快速帮助会很有帮助。
谢谢。
【问题讨论】:
标签: apache-spark apache-spark-sql spark-streaming spark-dataframe