【发布时间】：2022-04-05 19:21:04
【问题描述】：
由于 swipe() 已被弃用，我无法从左向右滑动屏幕。我的应用中有 4 个横幅，我想滑动查看所有横幅。
【问题讨论】：
-
使用触摸操作
标签： appium appium-android
【发布时间】：2022-04-05 19:21:04
【问题描述】：
这适用于所有方向：
枚举：
public enum DIRECTION {
DOWN, UP, LEFT, RIGHT;
}
实际代码：
public static void swipe(MobileDriver driver, DIRECTION direction, long duration) {
Dimension size = driver.manage().window().getSize();
int startX = 0;
int endX = 0;
int startY = 0;
int endY = 0;
switch (direction) {
case RIGHT:
startY = (int) (size.height / 2);
startX = (int) (size.width * 0.90);
endX = (int) (size.width * 0.05);
new TouchAction(driver)
.press(startX, startY)
.waitAction(Duration.ofMillis(duration))
.moveTo(endX, startY)
.release()
.perform();
break;
case LEFT:
startY = (int) (size.height / 2);
startX = (int) (size.width * 0.05);
endX = (int) (size.width * 0.90);
new TouchAction(driver)
.press(startX, startY)
.waitAction(Duration.ofMillis(duration))
.moveTo(endX, startY)
.release()
.perform();
break;
case UP:
endY = (int) (size.height * 0.70);
startY = (int) (size.height * 0.30);
startX = (size.width / 2);
new TouchAction(driver)
.press(startX, startY)
.waitAction(Duration.ofMillis(duration))
.moveTo(startX, endY)
.release()
.perform();
break;
case DOWN:
startY = (int) (size.height * 0.70);
endY = (int) (size.height * 0.30);
startX = (size.width / 2);
new TouchAction(driver)
.press(startX, startY)
.waitAction(Duration.ofMillis(duration))
.moveTo(startX, endY)
.release()
.perform();
break;
}
}
用法：
swipe(driver,DIRECTION.RIGHT);
希望这会有所帮助，
【讨论】：
-
还没有测试，但是看起来UP和Down不太正确
-
对于最新的 Appium java 客户端 API，TouchAction.press() 方法只接受 PointerOption 而不是 ints。如果您在那里遇到问题，请查看@Harjeet 的答案。这对我有用。
试试下面的方法。它适用于 Appium 1.16.0 版本。 我创建了这个方法来根据屏幕上的特定元素位置向左或向右滑动。它需要3个参数 Element X：需要滑动触摸的元素的X坐标。 元素Y：元素的Y坐标。 方向：左/右
//method to left and right swipe on the screen based on coordinates
public void swipeAction(int Xcoordinate, int Ycoordinate, String direction) {
//get device width and height
Dimension dimension = driver.manage().window().getSize();
int deviceHeight = dimension.getHeight();
int deviceWidth = dimension.getWidth();
System.out.println("Height x Width of device is: " + deviceHeight + " x " + deviceWidth);
switch (direction) {
case "Left":
System.out.println("Swipe Right to Left");
//define starting and ending X and Y coordinates
int startX=deviceWidth - Xcoordinate;
int startY=Ycoordinate; // (int) (height * 0.2);
int endX=Xcoordinate;
int endY=Ycoordinate;
//perform swipe from right to left
new TouchAction((AppiumDriver) driver).longPress(PointOption.point(startX, startY)).moveTo(PointOption.point(endX, endY)).release().perform();
break;
case "Right":
System.out.println("Swipe Left to Right");
//define starting X and Y coordinates
startX=Xcoordinate;
startY=Ycoordinate;
endX=deviceWidth - Xcoordinate;
endY=Ycoordinate;
//perform swipe from left to right
new TouchAction((AppiumDriver) driver).longPress(PointOption.point(startX, startY)).moveTo(PointOption.point(endX, endY)).release().perform();
break;
}
}
获取元素 X,Y 坐标。试试下面的方法
int elementX= driver.findElement(elementLocator).getLocation().getX();
int elementY= driver.findElement(elementLocator).getLocation().getY();
【讨论】：
假设您创建了AndroidDriver 的driver 实例，您可以向左滑动：
// Get location of element you want to swipe
WebElement banner = driver.findElement(<your_locator>);
Point bannerPoint = banner.getLocation();
// Get size of device screen
Dimension screenSize = driver.manage().window().getSize();
// Get start and end coordinates for horizontal swipe
int startX = Math.toIntExact(Math.round(screenSize.getWidth() * 0.8));
int endX = 0;
TouchAction action = new TouchAction(driver);
action
.press(PointOption.point(startX, bannerPoint.getY()))
.waitAction(WaitOptions.waitOptions(Duration.ofMillis(500)))
.moveTo(PointOption.point(endX, bannerPoint.getY()))
.release();
driver.performTouchAction(action);
使用最新的appium-java-client 6.1.0 和 Appium 1.8.x 服务器
【讨论】：
这应该可行，
Dimension size = driver.manage().window().getSize();
System.out.println(size.height+"height");
System.out.println(size.width+"width");
System.out.println(size);
int startPoint = (int) (size.width * 0.99);
int endPoint = (int) (size.width * 0.15);
int ScreenPlace =(int) (size.height*0.40);
int y=(int)size.height*20;
TouchAction ts = new TouchAction(driver);
//for(int i=0;i<=3;i++) {
ts.press(PointOption.point(startPoint,ScreenPlace ))
.waitAction(WaitOptions.waitOptions(Duration.ofMillis(1000)))
.moveTo(PointOption.point(endPoint,ScreenPlace )).release().perform();
【讨论】：
这适用于 iOS 移动：
//Here i am trying to swipe list of images from right to left
//First i am getting parent element (table/cell) id
//Then using predicatestring am searching for the element present or not then trying to click
List<MobileElement> ele = getMobileElement(listBtnQuickLink).findElements(By.xpath(".//XCUIElementTypeButton"));
for(int i=1 ;i<=20;i++) {
MobileElement ele1 = ele.get(i);
String parentID = getMobileElement(listBtnQuickLink).getId();
HashMap<String, String> scrollObject = new HashMap<String, String>();
scrollObject.put("element", parentID); //This is parent element id (not same element)
scrollObject.put("predicateString", "label == '"+ele1.getText()+"'");
scrollObject.put("direction", "left");
driver.executeScript("mobile:swipe", scrollObject); // scroll to the target element
System.out.println("Element is visible : "+ele1.isDisplayed());
}【讨论】：
不幸的是，我注意到 TouchAction 在带有 Selenium 4 的 Android 11 上不起作用。所以如果你使用 Selenide 和 Appium，你可以试试这个：
public class SwipeToLeft implements Command<SelenideElement> {
@Nullable
@Override
public SelenideElement execute(SelenideElement proxy, WebElementSource locator, @Nullable Object[] args) throws IOException {
Selenide.sleep(2000);
var driver = WebDriverRunner.getWebDriver();
var element = proxy.getWrappedElement();
((JavascriptExecutor) driver).executeScript("mobile: swipeGesture", ImmutableMap.of(
"elementId", ((RemoteWebElement) element).getId(),
"direction", "left",
"percent", 0.75
));
return proxy;
}
}
然后你可以使用：
$('your seleniumLocator').shouldBe(visible).execute(new SwipeToLeft());
【讨论】：