如何在 DevOps Pipeline PowerShell 任务中设置变量并将该变量用作另一个任务的条件

Question

我查看了在 DevOps 管道中为任务设置变量和条件的各种示例，但我似乎无法完全理解我的用例。

我希望 PowerShell 任务将变量设置为 true 或 false，然后将该变量用作另一个任务的条件，该任务将创建工件。

到目前为止，我在网上阅读的内容是：

- task: PowerShell@2
  inputs:
    targetType: 'inline'
    script: |
      #Some logic here
      
      if ($logicEvaluatedToTrue) {
          Write-Host "Artifacts will be created"
          Write-Host "##vso[task.setvariable variable=requiresRelease;isSecret=false;isOutput=true;]$true"
      } 
      else {
          Write-Host "No artifacts will be created"
      }
    failOnStderr: true

- task: PowerShell@2
  inputs:
    targetType: 'inline'
    script: |
       #Both of these do not contain any values
       Write-Host $env:requiresRelease
       Write-Host $requiresRelease
    failOnStderr: true

# this just evaluates to Expanded: and(True, eq(Null, 'true'))
- task: PublishPipelineArtifact@1
  condition: and(succeeded(), eq(variables.requiresRelease, 'true'))
  inputs:
    targetPath: 'snip1.zip'
    artifact: 'snip1'
    publishLocation: 'pipeline'

# this just evaluates to Expanded: and(True, eq(Null, 'true')) too
- task: PublishPipelineArtifact@1
  condition: and(succeeded(), eq(variables['requiresRelease'], 'true'))
  inputs:
    targetPath: 'snip2.txt'
    artifact: 'snip2'
    publishLocation: 'pipeline'

我尝试过像这样先设置一个变量：

variables:
  #existing vars first
  requiresRelease: false

但是当我这样做时，条件的评估变为Expanded: and(True, eq('false', 'true')) 。您的任何帮助将不胜感激。

Answer 1

您需要在分配值时删除isOutput=true：

Write-Host "##vso[task.setvariable variable=requiresRelease;isSecret=false;]$true"

要打印值，请使用以下语法：

Write-Host $(requiresRelease)