循环浏览我的列表以显示 .xml 上的信息

Question

我正在尝试创建 .xml 的副本，并且需要像这样呈现它（在需要的地方放置信息）：

    <FMEA>
      <Component>
        <Name></Name>
          <BasicEvent ID="">
            <Name></Name>
            <ShortName></ShortName>
            <Description></Description>
            <Unavailability></Unavailability>
          </BasicEvent>
          <BasicEvent ID="">
            <Name></Name>
            <ShortName></ShortName>
            <Description></Description>
            <Unavailability></Unavailability>
          </BasicEvent>
          <BasicEvent ID="">
            <Name></Name>
            <ShortName></ShortName>
            <Description></Description>
            <Unavailability></Unavailability>            
          </BasicEvent>
        //And so on...
      </Component>   
    </FMEA>

我确定我的课程是正确的，但我不确定如何循环遍历我创建的列表以将信息放置在正确的位置。我的代码 ID 在下面，非常感谢您提供的任何帮助。谢谢-K

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Xml;
using System.Xml.Linq;
using System.Xml.Serialization;

namespace ACW
{
class Program
{
    const string FILENAME = @"SmallResults.xml";
    static void Main(string[] args)
    {
        XDocument doc = XDocument.Load(FILENAME);
        FMEA fmea = new FMEA();
        fmea.comps = doc.Descendants("FMEA").Select(x => new Component()
        {
            Name = (string)x.Element("Name"),
            BasicEvent = x.Elements("BasicEvent").Select(y => BasicEvent.FindBasicEvent(y)).ToList()
        }).ToList();
        foreach(Component comp in fmea.comps)
        {
            new XmlSerializer(typeof(Component)).Serialize(Console.Out, comp);
            //I'm sure something goes here... A foreach loop or something...
        }
        Console.ReadKey();
    }
}
public class Component
{
    public string Name { get; set; }
    public List<BasicEvent> BasicEvent { set; get; }
}
public class BasicEvent
{
    public string Name { set; get; }
    public string ShortName { set; get; }
    public string Description { set; get; }
    public string Unavalability { set; get; }

    public static BasicEvent FindBasicEvent(XElement BasicEvent)
    {
        BasicEvent NewBasicEvent = new BasicEvent();
        NewBasicEvent.Name = (string)BasicEvent.Element("Name");
        NewBasicEvent.ShortName = (string)BasicEvent.Element("ShortName");
        NewBasicEvent.Description = (string)BasicEvent.Element("Description");
        NewBasicEvent.Unavalability = (string)BasicEvent.Element("Unavalability");
        return NewBasicEvent;
    }
}
class FMEA
{
    public List<Component> comps { get; set; }
}

}

Answer 1

复制 xml 有什么困难？

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication1
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            XDocument doc = XDocument.Load(FILENAME);

            XDocument duplicate = XDocument.Parse(doc.ToString());
        }
    }
}