【发布时间】:2020-12-04 23:29:58
【问题描述】:
我正在尝试做一个纸牌游戏(用户对电脑),首先获得 7.5 分的人获胜。为此,我创建了一套有 4 套套装,每套 10 张牌的套牌。卡片从 1 到 10,卡片的价值从 1 到 7,他们看重他们拥有的数字。卡片 8,9 和 10 值 0.5 分。
在有人在这里帮助我card game - what to put between the square brackets [ ]? 之后,我对我的代码进行了一些更改,现在我得到了如下所示。问题是我不知道如何发表声明说:如果所有卡片都已被选中(即数组'draw'全部设置为1),游戏结束。有人可以帮我吗?
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <math.h>
int main()
{
srand(time(NULL));
int key, card, cardpc, n;
int deck[40] = {
1, 1, 1, 1,
2, 2, 2, 2,
3, 3, 3, 3,
4, 4, 4, 4,
5, 5, 5, 5,
6, 6, 6, 6,
7, 7, 7, 7,
8, 8, 8, 8,
9, 9, 9, 9,
10, 10, 10, 10
};
int draw[40] = { 0 };
//array to "delete" a card. Mark a card as "deleted", e.g., by setting it to 1,
// then if the card chosen has been deleted, it choose again.
float points, points_pc;
points = 0;
points_pc = 0;
printf("Press 1 to play or 0 to not!\t");
scanf("%d", &key);
printf("\n");
if (key == 0) {
printf("BYE\n");
} else if (key == 1) {
while (key == 1) {
n = deck[rand() % 40];
card = deck[n];
if (draw[n] == 1) {
n = deck[rand() % 40];
card = deck[n];
}
if (card == 8 || card == 9 || card == 10) {
printf("You got 0.5 points");
points = points + 0.5;
} else {
printf("You got %d points", card);
points = points + card;
}
printf("\n");
printf("Your score is: %0.1f \n", points);
draw[n] = 1;
n = deck[rand() % 40];
cardpc = deck[n];
if (draw[n] == 1) {
n = deck[rand() % 40];
cardpc = deck[n];
}
if (cardpc == 8 || cardpc == 9 || cardpc == 10) {
printf("The PC got 0.5 points");
points_pc = points_pc + 0.5;
} else {
printf("The PC got %d points", cardpc);
points_pc = points_pc + cardpc;
}
printf("\n");
printf("The PC score is: %0.1f \n", points_pc);
draw[n] = 1;
printf("Do you want another card? (Press 1 if you want it)\t");
scanf("%d", &key);
printf("\n");
}
//if the user passes turn, the pc can still continue playing
while (points_pc < 7.5) {
n = deck[rand() % 40];
cardpc = deck[n];
if (draw[n] == 1) {
n = deck[rand() % 40];
cardpc = deck[n];
}
if (cardpc == 8 || cardpc == 9 || cardpc == 10) {
printf("The PC got 0.5 points");
points_pc = points_pc + 0.5;
} else {
printf("The PC got %d points", cardpc);
points_pc = points_pc + cardpc;
}
printf("\n");
printf("The PC score is: %0.1f \n", points_pc);
draw[n] = 1;
}
printf("\n");
}
//RESULTS
if ((points_pc >7.5) && (points > 7.5)){
printf("You both lost! \n");
} else if ((points == 7.5) || (points_pc > 7.5)) {
printf("You won! The PC score is above 7.5\n");
} else if ((points_pc == 7.5) || (points > 7.5)) {
printf("The PC won");
}
return 0;
}
【问题讨论】:
-
考虑使用不同的数据结构。虽然在这种情况下,拥有一个记录数组中剩余卡片数量的计数器似乎很容易,并在该计数器变为零时退出。
-
@WilliamPursell 谢谢!我以前没有考虑过。
-
要添加,同一张卡可以多次随机选择,因为如果之前已经选择过一张卡,只有一次重试(
draw[n] == 1)。这是预期的@Lusvi 吗? -
@Agus 为什么可以多次选择同一张卡?我认为通过做我所做的没关系...你能告诉我我有什么问题吗?
-
n = deck[rand() % 40]; card = deck[n]; if (draw[n] == 1) {n = deck[rand() % 40]; card = deck[n];}-> 这里说if (draw[n] == 1)你会做同样的过程,但这并不能保证当你再次调用rand() % 40时它会产生不同的价值
标签: arrays c if-statement