【问题标题】:Performance issues with SQLite3 sqlite3_step functionSQLite3 sqlite3_step 函数的性能问题
【发布时间】:2011-06-01 23:44:50
【问题描述】:

我在使用sqlite3_step 函数时遇到了特定查询的问题:

SELECT DISTINCT interfaces_int_id,device_dev_id FROM devInterface 
INNER JOIN interfaces ON devInterface.interfaces_int_id=interfaces.intf_id 
INNER JOIN nlink ON nlink.interfaces_intf_id=interfaces.intf_id 
INNER JOIN neighbor ON neighbor.neighbor_id=nlink.neighbor_neighbor_id 

我只发布了相关的查询部分。

为了查询数据库,我使用this code

调试的时候挂在

    while(true)
    {
--->    result = sqlite3_step(statement);

        if(result == SQLITE_ROW)
        {
            std::vector<std::string> values;
            ...
        }
        ...
    }

根据数据库大小,有时需要几分钟才能得到结果。但是在使用火狐插件“SQLite Manager”时,只需要1-2秒。

在查询需要几分钟时间的情况下,“neighbor”和“nlink”表的条目超过 150k。

为了构建数据库,我使用了 MySQL Workbench 工具的 Forward Engineer 功能,并修改了语法以适用于 sqlite3:

CREATE TABLE IF NOT EXISTS device(dev_id INTEGER PRIMARY KEY AUTOINCREMENT, type INT, hwtype INT, dataSource INT, hostname TEXT, sw_version TEXT, stpBridgeID TEXT, stpProtocol TEXT);

CREATE TABLE IF NOT EXISTS interfaces(intf_id INTEGER PRIMARY KEY AUTOINCREMENT, intfName TEXT, intfType TEXT, phl INT, macAddress TEXT, ipAddress TEXT, subnetMask TEXT, duplex TEXT, speed TEXT, status TEXT, description TEXT, l2l3 TEXT, errLvl INT, loadLvl INT, channel_intf_id INT, vpc_id INT, CONSTRAINT fk_interfaces_interfaces1 FOREIGN KEY (channel_intf_id) REFERENCES interfaces (intf_id) ON DELETE CASCADE ON UPDATE CASCADE);

CREATE TABLE IF NOT EXISTS devInterface (interfaces_int_id INT, device_dev_id INT, cdp_cdp_id INT, PRIMARY KEY (interfaces_int_id, device_dev_id, cdp_cdp_id), CONSTRAINT fk_dev_interface_interfaces1 FOREIGN KEY (interfaces_int_id) REFERENCES interfaces (intf_id) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT fk_dev_interface_device1 FOREIGN KEY (device_dev_id) REFERENCES device (dev_id) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT fk_devInterface_cdp1 FOREIGN KEY (cdp_cdp_id) REFERENCES cdp (cdp_id) ON DELETE CASCADE ON UPDATE CASCADE);

CREATE TABLE IF NOT EXISTS neighbor (neighbor_id INTEGER PRIMARY KEY AUTOINCREMENT, l2_addr TEXT NULL , l3_addr TEXT NULL);

CREATE TABLE IF NOT EXISTS nlink (neighbor_neighbor_id INT, interfaces_intf_id INT, PRIMARY KEY (neighbor_neighbor_id, interfaces_intf_id), CONSTRAINT fk_table1_neighbor1  FOREIGN KEY (neighbor_neighbor_id ) REFERENCES neighbor (neighbor_id) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT fk_table1_interfaces1 FOREIGN KEY (interfaces_intf_id) REFERENCES interfaces (intf_id) ON DELETE CASCADE ON UPDATE CASCADE);  

编辑:SQLITE 版本: 3.6.22

【问题讨论】:

    标签: c++ sqlite


    【解决方案1】:

    将SQLite升级到最新版本(3.7.6.2)后,性能好很多。

    【讨论】:

      猜你喜欢
      • 1970-01-01
      • 1970-01-01
      • 1970-01-01
      • 2021-03-17
      • 2011-07-18
      • 2022-01-26
      • 1970-01-01
      • 2020-02-15
      • 2013-09-12
      相关资源
      最近更新 更多