带有sqlite3的演示案例:
In [1]: import sqlite3
In [2]: conn = sqlite3.connect('example.db')
In [3]: c = conn.cursor()
In [4]: c.execute('''CREATE TABLE stocks
...: (date text, trans text, symbol text, qty real, price real)''')
...:
...: # Insert a row of data
...: c.execute("INSERT INTO stocks VALUES ('2006-01-05','BUY','RHAT',100,35.1
...: 4)")
...:
...: # Save (commit) the changes
...: conn.commit()
...:
In [5]: # Larger example that inserts many records at a time
...: purchases = [('2006-03-28', 'BUY', 'IBM', 1000, 45.00),
...: ('2006-04-05', 'BUY', 'MSFT', 1000, 72.00),
...: ('2006-04-06', 'SELL', 'IBM', 500, 53.00),
...: ]
...: c.executemany('INSERT INTO stocks VALUES (?,?,?,?,?)', purchases)
我可以获取与多个字符串匹配的值:
In [31]: c.execute('SELECT * FROM stocks WHERE symbol IN (?,?)',('IBM','RHAT'))
Out[31]: <sqlite3.Cursor at 0xaf703fa0>
In [32]: c.fetchall()
Out[32]:
[('2006-01-05', 'BUY', 'RHAT', 100.0, 35.14),
('2006-03-28', 'BUY', 'IBM', 1000.0, 45.0),
('2006-04-06', 'SELL', 'IBM', 500.0, 53.0)]
或者使用Parameter substitution for a SQLite "IN" clause的通用解决方案
In [33]: alist=['RHAT','IBM']
In [34]: c.execute('SELECT * FROM stocks WHERE symbol IN (%s)' %
...: ','.join('?'*len(alist)),
...: alist)
...:
Out[34]: <sqlite3.Cursor at 0xaf703fa0>
In [35]: c.fetchall()
Out[35]:
[('2006-01-05', 'BUY', 'RHAT', 100.0, 35.14),
('2006-03-28', 'BUY', 'IBM', 1000.0, 45.0),
('2006-04-06', 'SELL', 'IBM', 500.0, 53.0)]
c.execute('SELECT * FROM stocks WHERE symbol IN (:1,:2)',alist),可能还有其他形式。
另见:
sqlite3 "IN" clause
我假设MYSQL 和%sql iterface 的行为相同;但我没有安装这些。
使用正确的引用文字也可以工作(再次sqlite3)
c.execute('SELECT * FROM stocks WHERE symbol IN ("IBM","RHAT")')
或
In [80]: 'SELECT * FROM stocks WHERE symbol IN (%s)'%','.join('"%s"'%x for x in alist)
Out[80]: 'SELECT * FROM stocks WHERE symbol IN ("RHAT","IBM")'
In [81]: c.execute(_)
所以我猜:
%sql SELECT * FROM stocks WHERE symbol IN ("IBM","RHAT")
即使某种形式的(:....) 不起作用也可以。
我安装了%sql
In [5]: %%sql
...: sqlite:///example.db
...:
Out[5]: 'Connected: None@example.db'
In [7]: %sql SELECT * from stocks
Done.
Out[7]:
[('2006-01-05', 'BUY', 'RHAT', 100.0, 35.14),
('2006-03-28', 'BUY', 'IBM', 1000.0, 45.0),
('2006-04-05', 'BUY', 'MSFT', 1000.0, 72.0),
('2006-04-06', 'SELL', 'IBM', 500.0, 53.0)]
In [9]: %sql SELECT * from stocks where symbol in ('IBM')
Done.
Out[9]:
[('2006-03-28', 'BUY', 'IBM', 1000.0, 45.0),
('2006-04-06', 'SELL', 'IBM', 500.0, 53.0)]
In [10]: %sql SELECT * from stocks where symbol in ('IBM','RHAT')
Done.
Out[10]:
[('2006-01-05', 'BUY', 'RHAT', 100.0, 35.14),
('2006-03-28', 'BUY', 'IBM', 1000.0, 45.0),
('2006-04-06', 'SELL', 'IBM', 500.0, 53.0)]
字符串格式化方法有效:
In [11]: alist=['RHAT','IBM']
In [12]: cmd='SELECT * FROM stocks WHERE symbol IN (%s)'%','.join('"%s"'%x for x
...: in alist)
In [13]: cmd
Out[13]: 'SELECT * FROM stocks WHERE symbol IN ("RHAT","IBM")'
In [14]: %sql $cmd
Done.
Out[14]:
[('2006-01-05', 'BUY', 'RHAT', 100.0, 35.14),
('2006-03-28', 'BUY', 'IBM', 1000.0, 45.0),
('2006-04-06', 'SELL', 'IBM', 500.0, 53.0)]
: 语法没有很好的文档记录。目前尚不清楚是谁在实施它。 ($ 是标准的 Ipython 变量替换)。
In [18]: sym='IBM'
In [19]: %sql SELECT * from stocks where symbol in (:sym)
Done.
Out[19]:
[('2006-03-28', 'BUY', 'IBM', 1000.0, 45.0),
('2006-04-06', 'SELL', 'IBM', 500.0, 53.0)]
symbol in (:sym1,:sym2) 有效
到目前为止,我没有看到%sql 与传统的 SQL 占位符语法一起使用的证据。
看起来你 (?) 在 github 上提交并关闭了一个问题,https://github.com/catherinedevlin/ipython-sql/issues/92
调整该解决方案以引用字符串:
In [74]: mystring = '({})'.format(','.join('"{}"'.format(e) for e in alist))
In [75]: mystring
Out[75]: '("RHAT","IBM")'
In [76]: %sql SELECT * from stocks where symbol in $mystring
Done.
换句话说,使用ipython $ 注入而不是: 形式。
看ipython-sql源码:
ipython-sql/blob/master/src/sql/run.py
def run(conn, sql, config, user_namespace):
...
txt = sqlalchemy.sql.text(statement)
result = conn.session.execute(txt, user_namespace)
看起来:name 语法是sqlalchemy 绑定参数,并使用sqlalchemy.sql.text 和sqlalchemy.sql.bindparam 处理
(http://docs.sqlalchemy.org/en/latest/orm/tutorial.html#orm-tutorial-literal-sql)
此错误表明每个绑定参数都被转换为? 占位符,加上匹配的parameters 条目:
In [96]: %sql SELECT * from stocks where symbol in :mystring
(sqlite3.OperationalError) near "?": syntax error [SQL: 'SELECT * from stocks where symbol in ?'] [parameters: ('("RHAT","IBM")',)]
所以我最初生成IN (?,?,...) 以匹配列表长度的解决方案是正确的SQL,即使它不适用于sqlalchemy 和%sql。