在 VIEW PostgreSQL 中合并 IN 查询

Question

我有两张桌子

1. 相机
2. 相机分享

还有一个用户表。

在 Cameras 表中有一个列 owner_id，在 Camera Shares 表中有一个列 user_id。

现在还有其他 3 个表格，例如

1. 档案
2. 比较
3. 延时摄影

上面的每个表格都有一个camera_id，通过它连接到相机。

现在我创建了一个视图，它结合了这 3 个表中的所有数据

1. 档案
2. 比较
3. 延时摄影

但是要从该 VIEW 中获取相机列表的数据。这些是我正在做的步骤。

1. 获取用户提供的 user_id
2. 查询 owner_id 等于 user_id 的相机表并获取相机 ID。
3. 查询 user_id 等于 user_id 的相机共享表并获取相机 ID。
4. 结合第 2 步和第 3 步中的相机 ID。
5. 针对camera_ids 执行 IN 查询以查看

我的问题：

是否有可能以结合用户数据的方式创建 VIEW。当在 where 子句中传递 user_id 时，它会执行 VIEW 中的第 2、3、4 步。？任何帮助都会很棒。

这是我的观点

  CREATE VIEW archives_view AS
  WITH CORE AS (
    SELECT
      'ARCHIVES' AS TAB_NAME,
      ARC.TITLE,
      ARC.EXID,
      ARC.CREATED_AT,
      ARC.FROM_DATE,
      ARC.TO_DATE,
      NULL AS EMBED_CODE,
      ARC.FILE_NAME,
      ARC.FRAMES,
      ARC.URL,
      ARC.PUBLIC,
      ARC.STATUS,
      ARC.TYPE,
      NULL AS EXTRA,
      ARC.REQUESTED_BY,
      ARC.CAMERA_ID
    FROM
      PUBLIC.ARCHIVES AS ARC
    UNION ALL
    SELECT
      'TIMELAPSES',
      TL.TITLE,
      TL.EXID,
      TL.INSERTED_AT,
      TL.FROM_DATETIME,
      TL.TO_DATETIME,
      NULL AS EMBED_CODE,
      NULL AS FILE_NAME,
      NULL AS FRAMES,
      NULL AS URL,
      NULL AS PUBLIC,
      TL.STATUS,
      NULL AS TYPE,
      TL.EXTRA,
      TL.USER_ID,
      TL.CAMERA_ID
    FROM
      PUBLIC.TIMELAPSES AS TL
    UNION ALL
    SELECT
      'COMPARES',
      COMP.EXID,
      COMP.NAME,
      COMP.INSERTED_AT,
      COMP.BEFORE_DATE,
      COMP.AFTER_DATE,
      COMP.EMBED_CODE,
      NULL AS FILE_NAME,
      NULL AS FRAMES,
      NULL AS URL,
      COMP.PUBLIC,
      COMP.STATUS,
      NULL AS TYPE,
      NULL AS EXTRA,
      COMP.REQUESTED_BY,
      COMP.CAMERA_ID
    FROM
      PUBLIC.COMPARES AS COMP ),
    MORE_INFO AS (
      SELECT
        C.*,
        TRIM(CONCAT(U.FIRSTNAME, ' ', U.LASTNAME)) AS REQUESTER_NAME,
        U.EMAIL AS REQUESTER_EMAIL,
        CAM.EXID AS CAMERA_EXID,
        CAM.NAME,
        CAM.NAME AS CAMERA_NAME,
        CAM.TIMEZONE AS CAMERA_TIMEZONE,
        U.ID AS USER_ID
      FROM
        CORE C
      JOIN USERS U ON
        C.REQUESTED_BY = U.ID
      JOIN CAMERAS CAM ON
        C.CAMERA_ID = CAM.ID )
      SELECT
        *
      FROM
        MORE_INFO
      order by CREATED_AT DESC;

如果您想使用数据库和数据，则可以使用 DDL here。

Answer 1

返回表格而不是视图的函数

CREATE FUNCTION archives_view(int) RETURNS TABLE(
  tab_name text,
  title    text,
  exid     text,
  created_at timestamptz,
  from_date  timestamptz,
  to_date    timestamptz,
  embed_code text,
  file_name  text,
  frames     int,
  url        text,
  public boolean,
  status int,
  type   text,
  extra  json,
  requested_by int,
  camera_id int,
  requester_name text,
  requester_email text, 
  camera_exid text, 
  name text,    
  camera_name text,
  camera_timezone text,
  user_id int
)
AS
$$ 
  WITH CORE AS (
    SELECT
      'ARCHIVES' AS TAB_NAME,
      ARC.TITLE,
      ARC.EXID,
      ARC.CREATED_AT,
      ARC.FROM_DATE,
      ARC.TO_DATE,
      NULL AS EMBED_CODE,
      ARC.FILE_NAME,
      ARC.FRAMES,
      ARC.URL,
      ARC.PUBLIC,
      ARC.STATUS,
      ARC.TYPE,
      NULL AS EXTRA,
      ARC.REQUESTED_BY,
      ARC.CAMERA_ID
    FROM
      PUBLIC.ARCHIVES AS ARC
    UNION ALL
    SELECT
      'TIMELAPSES',
      TL.TITLE,
      TL.EXID,
      TL.INSERTED_AT,
      TL.FROM_DATETIME,
      TL.TO_DATETIME,
      NULL AS EMBED_CODE,
      NULL AS FILE_NAME,
      NULL AS FRAMES,
      NULL AS URL,
      NULL AS PUBLIC,
      TL.STATUS,
      NULL AS TYPE,
      TL.EXTRA,
      TL.USER_ID,
      TL.CAMERA_ID
    FROM
      PUBLIC.TIMELAPSES AS TL
    UNION ALL
    SELECT
      'COMPARES',
      COMP.EXID,
      COMP.NAME,
      COMP.INSERTED_AT,
      COMP.BEFORE_DATE,
      COMP.AFTER_DATE,
      COMP.EMBED_CODE,
      NULL AS FILE_NAME,
      NULL AS FRAMES,
      NULL AS URL,
      COMP.PUBLIC,
      COMP.STATUS,
      NULL AS TYPE,
      NULL AS EXTRA,
      COMP.REQUESTED_BY,
      COMP.CAMERA_ID
    FROM
      PUBLIC.COMPARES AS COMP ),
    MORE_INFO AS (
      SELECT
        C.*,
        TRIM(CONCAT(U.FIRSTNAME, ' ', U.LASTNAME)) AS REQUESTER_NAME,
        U.EMAIL AS REQUESTER_EMAIL,
        CAM.EXID AS CAMERA_EXID,
        CAM.NAME,
        CAM.NAME AS CAMERA_NAME,
        CAM.TIMEZONE AS CAMERA_TIMEZONE,
        U.ID AS USER_ID
      FROM
        CORE C
      JOIN USERS U ON
        C.REQUESTED_BY = U.ID AND U.ID = $1
      JOIN CAMERAS CAM ON
        C.CAMERA_ID = CAM.ID )
      SELECT
        *
      FROM
        MORE_INFO
$$
    LANGUAGE SQL;

使用，选择userId=1的数据

select * 
from archives_view(1)
order by CREATED_AT DESC;

db<>fiddle