【发布时间】：2012-04-10 09:49:47
【问题描述】：
这是一个测试页面。有一个按钮，单击时应将整个外部页面 extern2.php 加载到内容 div 中。 Extern2.php 可以在 Safari 和 Firefox 中使用，但是 index.php 只能在 Safari 中使用。
主页：
<!doctype html>
<html>
<head>
<meta charset="utf-8" />
<title>jQuery Ajax Test</title>
<script type="text/javascript" src="jquery_1.6.1.js"></script>
<script type="text/javascript">
function foo() {
$('#content').load('extern2.php', function() {
alert('Load was performed.');
});
}
</script>
<meta name="robots" content="index, follow, noarchive" />
<link rel="stylesheet" href="style.css" type="text/css" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js"></script>
</head>
<body>
<form action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post">
<input type="submit" name="formSubmit" value="Submit" />
</form>
<?php
if(isset($_POST['formSubmit']))
{
?>
<script type="text/javascript">
$(document).ready(function() {
$('#content').load('extern2.php');
});
</script>
<?
}
?>
<div id="content">Initial content in test.html</div>
</body>
</html>
外部页面：
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8" />
<title></title>
<meta name="robots" content="index, follow, noarchive" />
<link rel="stylesheet" href="style.css" type="text/css" />
<!-- This includes the ImageFlow CSS and JavaScript -->
<link rel="stylesheet" href="imageflow.packed.css" type="text/css" />
<script type="text/javascript" src="imageflow.packed.js"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js"></script>
</head>
<body>
<?php
// Connecting to database
$con = mysql_connect('CONNECT INFO HERE');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("CONNECT INFO HERE", $con);
$userID=2;
$getPage="SELECT * FROM pages,thumbnails WHERE thumbnails.thumbnailID=pages.thumbnailID AND pages.userID=".$userID." AND pages.projectID='8' LIMIT 3";
$pageResult = mysql_query($getPage) or die(" ". mysql_error());
?>
<!-- This is all the XHTML ImageFlow needs -->
<div id="myImageFlow" class="imageflow">
<? while($line = mysql_fetch_array($pageResult)) {
$thumb = $line['fileName'];
$title = $line['title'];
$link = $line['url'];
echo "<img src='../../thumbnails/small/".$thumb."' longdesc='".$link."' alt='".$title."' />";
}
?>
</div>
<?
mysql_close($con);
?>
</body>
</html>
【问题讨论】：