如何使用按钮单击创建新窗口[重复]答案

【问题标题】：How to create a new window with button click [duplicate]如何使用按钮单击创建新窗口[重复]
【发布时间】：2019-09-10 10:22:52
【问题描述】：

我想在单击按钮时创建一个新窗口。稍后我将根据输入的数据动态创建窗口。但我想先从简单的开始。

from PyQt5 import QtWidgets
from PyQt5.QtWidgets import QPushButton, QGridLayout, QWidget

class MyWindow(QtWidgets.QMainWindow, QPushButton):
    def __init__(self):
        super(MyWindow, self).__init__()
        centralWidget = QWidget()
        self.setCentralWidget(centralWidget)
        self.setWindowTitle("ASSET")
        self.Button = QPushButton('Action',self)
        self.Button.clicked.connect(self.Action)
        self.layout = QGridLayout(centralWidget)
        self.layout.addWidget(self.Button)


    def Action(self):
        pass

if __name__ == "__main__":
    import sys

    app = QtWidgets.QApplication(sys.argv)
    window = MyWindow()
    window.show()
    sys.exit(app.exec_())

【问题讨论】：

标签： python pyqt pyqt5

【解决方案1】：

您可以创建另一个QMainWindow()，并在单击按钮时激活show() 方法

from PyQt5 import QtWidgets
from PyQt5.QtWidgets import QPushButton, QGridLayout, QWidget, QLabel

class NewWindow(QtWidgets.QMainWindow):
    def __init__(self, parent=None):
        super(NewWindow, self).__init__(parent)

        self.label = QLabel('New Window!')
        centralWidget = QWidget()
        self.setCentralWidget(centralWidget)
        self.layout = QGridLayout(centralWidget)
        self.layout.addWidget(self.label)

class MyWindow(QtWidgets.QMainWindow, QPushButton):
    def __init__(self):
        super(MyWindow, self).__init__()
        centralWidget = QWidget()
        self.setCentralWidget(centralWidget)
        self.setWindowTitle("ASSET")
        self.Button = QPushButton('Action',self)
        self.Button.clicked.connect(self.Action)
        self.layout = QGridLayout(centralWidget)
        self.layout.addWidget(self.Button)

        self.new_window = NewWindow(self)

    def Action(self):
        self.new_window.show()

if __name__ == "__main__":
    import sys

    app = QtWidgets.QApplication(sys.argv)
    window = MyWindow()
    window.show()
    sys.exit(app.exec_())

【讨论】：