mysql "between and" 查询包括第一天和最后一天

Question

我有一个用于从数据库中提取数据的查询，但我发现它错过了第一天和最后一天。在此示例中，它跳过了将“scadenze”设置为“01-05-2021”的记录，并错过了将“scadenze”设置为“31-05-2021”的记录。我怎么能包括这些天？

这是我使用的查询：

$anno = date('Y'); // CURRENT YEAR
$mese = (date('m')+1); // THE MONTH THAT I NEED (THE NEXT ONE)

// FIRST DAY OF THE MONTH

$giornoinizio = '01';
$a = '';
$a .= $anno . '-' . $mese .'-' . $giornoinizio;

// LAST DAY OF THE MONTH

$giornofine = cal_days_in_month(CAL_GREGORIAN,$mese,$anno);
$b = '';
$b .= $anno . '-' . $mese .'-' . $giornofine;

$sql = "SELECT * FROM condominio WHERE scadenze BETWEEN '$a' AND '$b' ORDER BY scadenze ASC";

此查询“有效”，但它删除了第一天和最后一天。我如何才能包含它们？

谢谢

Answer 1

你让自己的生活变得相当困难。

您可以使用此日期代码简单地获取 2 个日期

$a = date('Y-m-d', strtotime('first day of +1 month'));
$b =  date('Y-m-d', strtotime('last day of +1 month'));

$sql = "SELECT * FROM condominio WHERE scadenze BETWEEN '$a' AND '$b' ORDER BY scadenze ASC";

但是这种将数据连接到查询中是一个坏习惯，进入它可以鼓励您SQL Injection Attack。 甚至if you are escaping inputs, its not safe! 你应该总是使用prepared parameterized statements 在MYSQLI_ 或PDO API 中，而不是将用户提供的值连接到查询中。

不确定您使用的是哪个扩展，所以我只能建议一个 PDO 解决方案

$a = date('Y-m-d', strtotime('first day of +1 month'));
$b =  date('Y-m-d', strtotime('last day of +1 month'));

$sql = "SELECT * FROM condominio
        WHERE scadenze BETWEEN :a AND :b 
        ORDER BY scadenze ASC";
$stmt = $con->prepare($sql);
$stmt->execute([':a'=>$a, ':b'=>$b]);

$result = $stmt->fetchAll();

foreach ( $results as $row ){
    // process each row
}

Answer 2

尝试在你的列上使用 date() 函数

SELECT * FROM condominio WHERE date(scadenze) BETWEEN '$a' AND '$b' ORDER BY scadenze ASC