【发布时间】:2014-08-25 15:30:25
【问题描述】:
我试图通过 API 将文件上传到 Web 服务器,但出现错误 “远程服务器返回错误:(403) Forbidden。”我也尝试通过邮递员上传文件,它是成功的。下面是我的代码上传文件和邮递员预览。
public static void HttpUploadFile(string url, string file, string paramName, string contentType, NameValueCollection nvc)
{
MessageBox.Show(string.Format("Uploading {0} to {1}", file, url));
var boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x");
var boundarybytes = Encoding.ASCII.GetBytes("\r\n--" + boundary + "\r\n");
var wr = (HttpWebRequest)WebRequest.Create(url);
wr.ContentType = "multipart/form-data; boundary=" + boundary;
wr.Method = "POST";
wr.KeepAlive = true;
wr.Credentials = CredentialCache.DefaultCredentials;
var rs = wr.GetRequestStream();
const string formdataTemplate = "Content-Disposition: form-data; name=\"{0}\"\r\n\r\n{1}";
foreach (string key in nvc.Keys)
{
rs.Write(boundarybytes, 0, boundarybytes.Length);
var formitem = string.Format(formdataTemplate, key, nvc[key]);
byte[] formitembytes = Encoding.UTF8.GetBytes(formitem);
rs.Write(formitembytes, 0, formitembytes.Length);
}
rs.Write(boundarybytes, 0, boundarybytes.Length);
const string headerTemplate = "Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"\r\nContent-Type: {2}\r\n\r\n";
var header = string.Format(headerTemplate, paramName, file, contentType);
var headerbytes = Encoding.UTF8.GetBytes(header);
rs.Write(headerbytes, 0, headerbytes.Length);
var fileStream = new FileStream(file, FileMode.Open, FileAccess.Read);
var buffer = new byte[4096];
var bytesRead = 0;
while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0)
{
rs.Write(buffer, 0, bytesRead);
}
fileStream.Close();
var trailer = Encoding.ASCII.GetBytes("\r\n--" + boundary + "--\r\n");
rs.Write(trailer, 0, trailer.Length);
rs.Close();
WebResponse wresp = null;
try
{
wresp = wr.GetResponse();
var stream2 = wresp.GetResponseStream();
var reader2 = new StreamReader(stream2);
MessageBox.Show(string.Format("Response is: {0}", reader2.ReadToEnd()));
}
catch (Exception ex)
{
MessageBox.Show("Error uploading file" + ex);
if (wresp != null)
{
wresp.Close();
wresp = null;
}
}
finally
{
wr = null;
}
}
这是邮递员预览
POST / HTTP/1.1
Host: buckname.s3.amazonaws.com
Cache-Control: no-cache
----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="key"
2014/6b9830b098c9871c6356a5e55af91bfd/${filename}
----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="AWSAccessKeyId"
AKIAJNXK6LUBUSZBXJIQ
----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="acl"
public-read
----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="policy"
eyJleHBpcmF0aW9uIjoiMjAxNC0wOC0yMlQxMDo1MTow
----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="signature"
ezYsOF/P6bGcOqQdyJeE7iApu2A=
----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="success_action_status"
201
----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="secure"
true
----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="x-amz-storage-class"
REDUCED_REDUNDANCY
----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="file"; filename="exp.png"
Content-Type: image/png
----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="Content-Type"
image/jpeg
----WebKitFormBoundaryE19zNvXGzXaLvS5C
编辑(代码发送)
var nvc = new NameValueCollection
{
{"AWSAccessKeyId", fields.AWSAccessKeyId},
{"Content-Type", "image/jpeg"},
{"acl", fields.acl},
{"key", fields.key},
{"policy", fields.policy},
{"secure", secure.ToString()},
{"signature", signature},
{"success_action_status", fields.success_action_status},
{"x-amz-storage-class", "REDUCED_REDUNDANCY"}
};
HttpUploadHelper.HttpUploadFile(responsFieldsDeSerial.url.ToString(),@"C:\1.png", "file", "image/jpeg",nvc);
谢谢!
【问题讨论】:
-
你的代码产生了什么? (您是否尝试过有效内容和无效内容之间的差异?)
-
AccessDenied根据策略无效:策略条件失败:[" eq", "$Secure", "true"] @Richard -
不,您的代码 sending 是什么(即在 POST 请求中发送的输出是什么)。建议使用 Fiddler 或其他 HTTP 调试器。
-
对不起,我添加了代码发送,我尝试使用 HTTP 调试器,如 postman(chrome 扩展)。 @理查德
-
您需要捕获代码发送的内容(标头和正文),并与有效的 POST 进行比较。您的编码代码可能存在缺陷。总体方法:修复您的代码以匹配有效的内容(然后使用类似的请求进行迭代)。因此建议使用 Fiddler 来准确查看您的代码发送的内容。
标签: c# httpwebrequest multipartform-data