使用 SQL 将 Oracle 的 RAW(16) 转换为 .NET 的 GUID

Question

如何在 MSSQL 中将 Oracle Raw 16 转换为 GUID？以下在 Oracle DB SQL 控制台中不起作用，

select hextoraw(Raw16Column), *
from OracleDb.PRODUCTS
order by PRODUCTS_ID desc
fetch next 20 rows only

错误：

[42000][936] ORA-00936: missing expression Position: 23

资源：Convert from Oracle's RAW(16) to .NET's GUID

https://docs.oracle.com/cd/B19306_01/server.102/b14200/functions064.htm

Answer 1

如果您使用* 并且还选择其他列，那么您必须在* 前面加上表名或别名（您可能需要RAWTOHEX 而不是HEXTORAW）：

select p.*,
       RAWTOHEX(raw16column)
from   PRODUCTS p
order by PRODUCTS_ID desc
fetch next 20 rows only

如果你想convert it to a GUID with the correct endianess 那么：

select p.*,
       SUBSTR(raw16column,7,2)
       ||SUBSTR(raw16column,5,2)
       ||SUBSTR(raw16column,3,2)
       ||SUBSTR(raw16column,1,2)
       ||'-'
       ||SUBSTR(raw16column,11,2)
       ||SUBSTR(raw16column,9,2)
       ||'-'
       ||SUBSTR(raw16column,15,2)
       ||SUBSTR(raw16column,13,2)
       ||'-'
       ||SUBSTR(raw16column,17,16)
         AS guid
from   PRODUCTS p
order by PRODUCTS_ID desc
fetch next 20 rows only

db小提琴here