Android SQLite 没有按照我告诉它的顺序插入

Question

我有一个对象，它被调用来向数据库添加一行，但由于我无法弄清楚的原因，它试图不按我告诉它的顺序插入它。

这是方法的代码

public Coin createCoin(String create_year, String create_specialty, String create_mintage,  String create_mint, int create_have) {
    ContentValues values = new ContentValues();
    values.put(MySQLiteHelper.MINT, create_mint);
    values.put(MySQLiteHelper.YEAR, create_year);
    values.put(MySQLiteHelper.MINTAGE, create_mintage);
    values.put(MySQLiteHelper.HAVE, create_have);
    values.put(MySQLiteHelper.SPECIALTY, create_specialty);
    //(String table, String nullColumnHack, ContentValues values)
    long insertId = database.insert(MySQLiteHelper.TABLE_PENNY_FLYING_EAGLE, null,
            values);
    //(String table, String[] columns, String selection, String[] selectionArgs, String groupBy, String having, String orderBy, String limit)
    Cursor cursor = database.query(MySQLiteHelper.TABLE_PENNY_FLYING_EAGLE,
            allColumns, MySQLiteHelper.YEAR, null,
            null, null, null);
    cursor.moveToFirst();
    Coin newCoin = cursorToCoin(cursor);
    cursor.close();
    return newCoin;
}
public ArrayList<Coin> getAllCoins() {
    ArrayList<Coin> coins = new ArrayList<Coin>();
    Cursor cursor = database.query(MySQLiteHelper.TABLE_PENNY_FLYING_EAGLE,
            allColumns, null, null, null, null, null);
    cursor.moveToFirst();
    while (!cursor.isAfterLast()) {
        Coin coin = cursorToCoin(cursor);
        coins.add(coin);
        cursor.moveToNext();
    }
    // make sure to close the cursor
    cursor.close();
    return coins;
}
private Coin cursorToCoin(Cursor cursor) {
    Coin coin = new Coin();
    coin.setYear(cursor.getString(0));
    coin.setSpecialty(cursor.getString(1));
    coin.setMintage(cursor.getString(2));
    return coin;
}

现在我认为它会尝试将数据插入为

INSERT INTO penny_flying_eagle(mint,year,mintage,have,specialty) VALUES (?,?,?,?,?)

但它却给了我一个错误

66-1166/com.example.dommol.testlist E/SQLiteLog﹕ (1) table penny_flying_eagle has no column named mint
   02-03 21:31:42.097    1166-1166/com.example.dimmel.testlist E/SQLiteDatabase﹕ Error inserting mint=0 year=1858 mintage=24,600,000 specialty=Not NULL have=D
android.database.sqlite.SQLiteException: table penny_flying_eagle has no column named mint (code 1): , while compiling: INSERT INTO penny_flying_eagle(mint,year,mintage,specialty,have) VALUES (?,?,?,?,?)

我的想法是它告诉我there is no column named mint，因为它试图将mint 放在year 的位置并且没有在那里找到该列。为什么这试图以与我指定的顺序不同的顺序插入值？

编辑：创建表的代码

public class MySQLiteHelper extends SQLiteOpenHelper {

public static final String TABLE_PENNY_FLYING_EAGLE = "penny_flying_eagle";
public static final String YEAR = "year";
public static final String SPECIALTY = "specialty";
public static final String MINTAGE = "mintage";
public static final String HAVE = "have";
public static final String MINT = "mint";

private static final String DATABASE_NAME = "coins.db";
private static final int DATABASE_VERSION = 1;

// Database creation sql statement
private static final String DATABASE_CREATE = "create table "
        + TABLE_PENNY_FLYING_EAGLE + "("
        + MINT + " text, "
        + YEAR + " text, "
        + MINTAGE + " text not null, "
        + SPECIALTY + " text, "
        + HAVE + " integer, "
        + "primary key (" + YEAR + ", " + SPECIALTY + ", " + MINTAGE + ") on conflict ignore );";

public MySQLiteHelper(Context context) {
    super(context, DATABASE_NAME, null, DATABASE_VERSION);
}

@Override
public void onCreate(SQLiteDatabase database) {
    database.execSQL(DATABASE_CREATE);

Answer 1

这个问题有两个原因：

1. 如果您重命名了列名。 （即 mint 列），因为一旦创建数据库，更改列名时不会更改表。

2. 如果您为已经存在的表添加了新的列名。（即 mint 列）

解决方案：

1. 将 DATABASE_VERSION 从 1 更改（升级）到 2 等等。

2. 从 data/data/"your app name"/databases/"your database" 中删除数据库并运行应用程序，以便创建新数据库。