窗口中球拍的 C++ 错误边距

Question

int width = 800;
int height = 600;
int interval = 1000 / 60;
int score_player1 = 0;
int score_player2 = 0;
int racket_width = 10;
int racket_height = 80;
int racket_speed = 8;
int racket_left_x = 10;
int racket_left_y = 50;
int racket_right_x = width - racket_width - 10;
int racket_right_y = 50;

完整代码（不含球类）：http://pastebin.com/TA9NkV5c

右侧球拍到窗口右侧的边距小于左侧。这些变量的计算是正确的，但仍然不相等。

http://i.imgur.com/2PA0pGz.png图片链接

Answer 1

您已将 窗口 设置为 800 像素的宽度，但其他所有内容都相对于客户区定位，该客户区比窗口宽度窄边框的厚度。

使用AdjustWindowRect 计算您必须制作窗口的大小，以使客户区达到所需大小。

// Initialize a RECT with the size you want the client area to be.
RECT rc = { 0, 0, width, height };
// Now adjust the rectangle to the size the window would need to be.
AdjustWindowRect(&rc, my_style_flags, FALSE);

// Now create the window using the sizes in rc.  Make sure you use
// consistent style flags or the adjustment may not be correct.
const int window_width = rc.right - rc.left;
const int window_height = rc.bottom - rc.top;
my_hwnd = CreateWindow(..., my_style_flags, x, y, window_width, window_height, ...);