Applescript 语法错误“预期为“else”等，但发现脚本结尾。”答案

【问题标题】：Applescript Syntax Error "Expected “else”, etc. but found end of script."Applescript 语法错误“预期为“else”等，但发现脚本结尾。”
【发布时间】：2013-03-02 07:53:06
【问题描述】：

我在 applescript 中遇到了这个问题：

display dialog "Open Which Application" buttons {"Chrome", "AppleScript", "Textedit"} 
set the button_pressed to the button returned of the result
if the button_pressed is "Chrome" then
Open application "Google Chrome"-- action for 1st button goes here
if the button_pressed is "Applescript" then
Open application "Applescript Editor"-- action for 2nd button goes here
if the button_pressed is "Textedit" then
Open application "Textedit"-- action for 3rd button goes here
end

它一直说 SYNTAX ERROR: Expected “else”, etc. but found end of script.

我该怎么办

【问题讨论】：

标签： syntax applescript

【解决方案1】：

您有三个if 语句，但您只有end 其中一个。

你可能想要的是else if:

display dialog "Open Which Application" buttons {"Chrome", "AppleScript", "Textedit"}
set the button_pressed to the button returned of the result
if the button_pressed is "Chrome" then
    open application "Google Chrome" -- action for 1st button goes here
else if the button_pressed is "Applescript" then
    open application "AppleScript Editor" -- action for 2nd button goes here
else if the button_pressed is "Textedit" then
    open application "TextEdit" -- action for 3rd button goes here
end if

（另外，你真的应该使用end if，而不仅仅是end，AppleScript Editor 会为你解决这个问题。）

或者，您可以end 一个：

display dialog "Open Which Application" buttons {"Chrome", "AppleScript", "Textedit"}
set the button_pressed to the button returned of the result
if the button_pressed is "Chrome" then
    open application "Google Chrome" -- action for 1st button goes here
end if
if the button_pressed is "Applescript" then
    open application "AppleScript Editor" -- action for 2nd button goes here
end if
if the button_pressed is "Textedit" then
    open application "TextEdit" -- action for 3rd button goes here
end if

但是，这些情况显然是互斥的，所以没有理由不使用else if。

如果有帮助，请逐行输入，看看 AppleScript Editor 是如何缩进的：

display dialog "Open Which Application" buttons {"Chrome", "AppleScript", "Textedit"} 
set the button_pressed to the button returned of the result
if the button_pressed is "Chrome" then
    Open application "Google Chrome"-- action for 1st button goes here
    if the button_pressed is "Applescript" then
        Open application "Applescript Editor"-- action for 2nd button goes here
        if the button_pressed is "Textedit" then
            Open application "Textedit"-- action for 3rd button goes here
        end

这应该很明显出了什么问题。

【讨论】：

【解决方案2】：

试试：

display dialog "Open Which Application" buttons {"Chrome", "AppleScript", "Textedit"}
set the button_pressed to the button returned of the result
if the button_pressed is "Chrome" then tell application "Google Chrome" to activate -- action for 1st button goes here 
if the button_pressed is "Applescript" then tell application "AppleScript Editor" to activate -- action for 2nd button goes here 
if the button_pressed is "Textedit" then tell application "TextEdit" to activate -- action for 3rd button goes here end

【讨论】：