【发布时间】:2018-12-19 07:53:37
【问题描述】:
我需要获取planes 及其所有对应的bookings 的列表,理想情况下还有一个飞机列表,其中每架飞机都有一个预订列表作为其属性之一,因此可以轻松地对其进行 json 编码。我怎样才能用 SQLAlchemy 做到这一点?我怀疑 SQLAlchemy 有一些强大的功能可以让这变得简单,我宁愿不必进行 2 次查询并处理结果。
例如结果:
Plane
- id: -- 1
- name: -- Eagle Bravo
- bookings: -- Booking1, Booking2, Booking3
Plane
- id: -- 2
- name: -- Charlie Bravo
- bookings: -- Booking4, Booking5, Booking6
Plane
- id: -- 3
- name: -- Alpha Bravo
- bookings: -- Booking7, Booking8, Booking9
飞机和预订模型:
class Booking(db.Model):
id = db.Column(db.Integer, primary_key=True)
start_date = db.Column(db.DateTime)
end_date = db.Column(db.DateTime)
person_id = db.Column(db.Integer, db.ForeignKey('person.id'))
person = db.relationship('Person', backref=db.backref('Bookings', lazy='dynamic'))
plane_id = db.Column(db.Integer, db.ForeignKey('plane.id'))
def __init__(self, start_date, end_date, person_id):
self.start_date = start_date
self.end_date = end_date
self.person_id = person_id
def __repr__(self):
return '<Booking... %r>'
def as_dict(self):
return {c.name: getattr(self, c.name) for c in self.__table__.columns}
class Plane(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(80))
def __init__(self, name):
self.name = name
def __repr__(self):
return '<Plane... %r>'
def as_dict(self):
return {c.name: getattr(self, c.name) for c in self.__table__.columns}
【问题讨论】:
标签: flask sqlalchemy flask-sqlalchemy