【发布时间】:2016-06-23 18:09:38
【问题描述】:
我正在尝试在 HSV 维度中执行 Sobel 运算符(我的指南告诉我在 HSV 中执行此操作,但我不明白为什么它在 HSV 上比在 RGB 上效果更好)。 我已经构建了一个从 RGB 转换为 HSV 的函数。虽然我在 C++ 方面有一些平庸的知识,但我对图像处理感到困惑,因此我试图使代码尽可能简单,这意味着我(在这个阶段)不关心时间和空间。 从我在灰度 bmp 照片中得到的结果来看,我的 V 和 S 似乎很好,但我的 H 看起来很乱。 我在这里有 2 个问题: 1. 一张正常的灰度级H照片与源照片相比应该如何? 2. 代码哪里错了:
void RGBtoHSV(unsigned char image[][NUMBER_OF_COLUMNS][NUMBER_OF_COLORS],
float Him[][NUMBER_OF_COLUMNS],
float Vim[][NUMBER_OF_COLUMNS],
float Sim[][NUMBER_OF_COLUMNS])
{
double Rn, Gn, Bn;
double C;
double H, S, V;
for (int row = 0; row < NUMBER_OF_ROWS; row++)
{
for (int column = 0; column < NUMBER_OF_COLUMNS; column++)
{
Rn = (1.0*image[row][column][R]) / 255;
Gn = (1.0*image[row][column][G] )/ 255;
Bn = (1.0*image[row][column][B] )/ 255;
//double RGBn[3] = { Rn, Gn, Bn };
double max = Rn;
if (max < Gn) max = Gn;
if (max < Bn) max = Bn;
double min = Rn;
if (min > Gn) min = Gn;
if (min > Bn) min = Bn;
C = max - min;
H = 0;
if (max==0)
{
S = 0;
H = -1; //undifined;
V = max;
}
else
{
/* if (max == Rn)
H = (60.0* ((int)((Gn - Bn) / C) % 6));
else if (max == Gn)
H = 60.0*( (Bn - Rn)/C + 2);
else
H = 60.0*( (Rn - Gn)/C + 4);
*/
if (max == Rn)
H = ( 60.0* ( (Gn - Bn) / C) ) ;
else if (max == Gn)
H = 60.0*((Bn - Rn) / C + 2);
else
H = 60.0*((Rn - Gn) / C + 4);
V = max; //AKA lightness
S = C / max; //saturation
}
while (H < 0)
H += 360;
while (H>360)
H -= 360;
Him[row][column] = (float)H;
Vim[row][column] = (float)V;
Sim[row][column] = (float)S;
}
}
}
也是我的 hsvtorgb :
void HSVtoRGB(unsigned char image[][NUMBER_OF_COLUMNS][NUMBER_OF_COLORS],
float Him[][NUMBER_OF_COLUMNS],
float Vim[][NUMBER_OF_COLUMNS],
float Sim[][NUMBER_OF_COLUMNS])
{
double R1, G1, B1;
double C;
double V;
double S;
double H;
int Htag;
double Htag2;
double x;
double m;
for (int row = 0; row < NUMBER_OF_ROWS; row++)
{
for (int column = 0; column < NUMBER_OF_COLUMNS; column++)
{
H = (double)Him[row][column];
S = (double)Sim[row][column];
V = (double)Vim[row][column];
C = V*S;
Htag = (int) (H / 60.0);
Htag2 = H/ 60.0;
//x = C*(1 - abs(Htag % 2 - 1));
double tmp1 = fmod(Htag2, 2);
double temp=(1 - abs(tmp1 - 1));
x = C*temp;
//switch (Htag)
switch (Htag)
{
case 0 :
R1 = C;
G1 = x;
B1 = 0;
break;
case 1:
R1 = x;
G1 = C;
B1 = 0;
break;
case 2:
R1 = 0;
G1 = C;
B1 = x;
break;
case 3:
R1 = 0;
G1 = x;
B1 = C;
break;
case 4:
R1 = x;
G1 = 0;
B1 = C;
break;
case 5:
R1 = C;
G1 = 0;
B1 = x;
break;
default:
R1 = 0;
G1 = 0;
B1 = 0;
break;
}
m = V - C;
//this is also good change I found
//image[row][column][R] = unsigned char( (R1 + m)*255);
//image[row][column][G] = unsigned char( (G1 + m)*255);
//image[row][column][B] = unsigned char( (B1 + m)*255);
image[row][column][R] = round((R1 + m) * 255);
image[row][column][G] = round((G1 + m) * 255);
image[row][column][B] = round((B1 + m) * 255);
}
}
}
void HSVfloattoGrayconvert(unsigned char grayimage[NUMBER_OF_ROWS] [NUMBER_OF_COLUMNS], float hsvimage[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS], char hsv)
{
//grayimage , flaotimage , h/s/v
float factor;
if (hsv == 'h' || hsv == 'H') factor = (float) 1 / 360;
else factor = 1;
for (int row = 0; row < NUMBER_OF_ROWS; row++)
{
for (int column = 0; column < NUMBER_OF_COLUMNS; column++)
{
grayimage[row][column] = (unsigned char) (0.5f + 255.0f * (float)hsvimage[row][column] / factor);
}
}
}
和我的主要:
unsigned char ColorImage1[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS] [NUMBER_OF_COLORS];
float Himage[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS];
float Vimage[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS];
float Simage[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS];
unsigned char ColorImage2[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS] [NUMBER_OF_COLORS];
unsigned char HimageGray[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS];
unsigned char VimageGray[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS];
unsigned char SimageGray[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS];
unsigned char HAfterSobel[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS];
unsigned char VAfterSobel[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS];
unsigned char SAfterSobal[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS];
unsigned char HSVcolorAfterSobal[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS][NUMBER_OF_COLORS];
unsigned char RGBAfterSobal[NUMBER_OF_ROWS][NUMBER_OF_COLUMNS][NUMBER_OF_COLORS];
int KernelX[3][3] = {
{-1,0,+1}, {-2,0,2}, {-1,0,1 }
};
int KernelY[3][3] = {
{-1,-2,-1}, {0,0,0}, {1,2,1}
};
void main()
{
//work
LoadBgrImageFromTrueColorBmpFile(ColorImage1, "P22A.bmp");
// add noise
AddSaltAndPepperNoiseRGB(ColorImage1, 350, 255);
StoreBgrImageAsTrueColorBmpFile(ColorImage1, "saltandpepper.bmp");
AddGaussNoiseCPPstileRGB(ColorImage1, 0.0, 1.0);
StoreBgrImageAsTrueColorBmpFile(ColorImage1, "Saltandgauss.bmp");
//saves hsv in float array
RGBtoHSV(ColorImage1, Himage, Vimage, Simage);
//saves hsv float arrays in unsigned char arrays
HSVfloattoGrayconvert(HimageGray, Himage, 'h');
HSVfloattoGrayconvert(VimageGray, Vimage, 'v');
HSVfloattoGrayconvert(SimageGray, Simage, 's');
StoreGrayImageAsGrayBmpFile(HimageGray, "P22H.bmp");
StoreGrayImageAsGrayBmpFile(VimageGray, "P22V.bmp");
StoreGrayImageAsGrayBmpFile(SimageGray, "P22S.bmp");
WaitForUserPressKey();
}
编辑:更改代码 + 添加方程式来源: Soruce:对于方程:
- http://www.rapidtables.com/convert/color/hsv-to-rgb.htm
- http://www.rapidtables.com/convert/color/rgb-to-hsv.htm
编辑3: 听取@gpasch 的建议并使用better reference 并删除mod6 我现在可以恢复RGB 原始照片了!但不幸的是,现在我的灰度照片比以前更加混乱。 我将编辑有关的代码,以便获得有关如何保存 H 灰度照片的更多信息。
【问题讨论】:
-
对于灰度图像,S(饱和度)应该为零,H(色调)未定义,或者由于其值(色轮上的角度)没有意义而采用一些规范角度灰色阴影。
-
@ChristopherOicles 可以将 S 设置为 0 但 H 呢?我将添加另一段可能也有问题的代码
-
C == 0表示像素为黑色、白色或灰色。H在这种情况下没有意义,所以任意设置为0,只是为了给这些情况下H的一致值。 -
你从哪里得到转换的方程式?
-
@gpasch from : 5. rapidtables.com/convert/color/hsv-to-rgb.htm 6. rapidtables.com/convert/color/rgb-to-hsv.htm 也将添加编辑此资源
标签: c++ image c++11 image-processing