【发布时间】:2012-05-04 01:30:55
【问题描述】:
我是计算机视觉方面的新手,但我需要在 C++ 中创建一个小函数,即使是打印在他身上的东西也会检测到一张白纸,并且检索 4 个边缘来协调我真正需要的东西所以我可以使用这些坐标并剪切另一个jpg文件并将剪切后的图像用作opengl纹理。 我不知道如何检测纸张。 尝试搜索计算机视觉,发现我必须对图像进行阈值处理,进行标记然后使用边缘检测或哈里斯检测,但没有找到任何教程。 谁能帮我解决这个问题,或者给我一些可以帮助我的教程?
只要找到这个:
int arDetectMarker( ARUint8 *dataPtr, int thresh,
ARMarkerInfo **marker_info, int *marker_num )
{
ARInt16 *limage;
int label_num;
int *area, *clip, *label_ref;
double *pos;
double rarea, rlen, rlenmin;
double diff, diffmin;
int cid, cdir;
int i, j, k;
*marker_num = 0;
limage = arLabeling( dataPtr, thresh,
&label_num, &area, &pos, &clip, &label_ref );
if( limage == 0 ) return -1;
marker_info2 = arDetectMarker2( limage, label_num, label_ref,
area, pos, clip, AR_AREA_MAX, AR_AREA_MIN,
1.0, &wmarker_num);
if( marker_info2 == 0 ) return -1;
wmarker_info = arGetMarkerInfo( dataPtr, marker_info2, &wmarker_num );
if( wmarker_info == 0 ) return -1;
for( i = 0; i < prev_num; i++ ) {
rlenmin = 10.0;
cid = -1;
for( j = 0; j < wmarker_num; j++ ) {
rarea = (double)prev_info[i].marker.area / (double)wmarker_info[j].area;
if( rarea < 0.7 || rarea > 1.43 ) continue;
rlen = ( (wmarker_info[j].pos[0] - prev_info[i].marker.pos[0])
* (wmarker_info[j].pos[0] - prev_info[i].marker.pos[0])
+ (wmarker_info[j].pos[1] - prev_info[i].marker.pos[1])
* (wmarker_info[j].pos[1] - prev_info[i].marker.pos[1]) ) / wmarker_info[j].area;
if( rlen < 0.5 && rlen < rlenmin ) {
rlenmin = rlen;
cid = j;
}
}
if( cid >= 0 && wmarker_info[cid].cf < prev_info[i].marker.cf ) {
wmarker_info[cid].cf = prev_info[i].marker.cf;
wmarker_info[cid].id = prev_info[i].marker.id;
diffmin = 10000.0 * 10000.0;
cdir = -1;
for( j = 0; j < 4; j++ ) {
diff = 0;
for( k = 0; k < 4; k++ ) {
diff += (prev_info[i].marker.vertex[k][0] - wmarker_info[cid].vertex[(j+k)%4][0])
* (prev_info[i].marker.vertex[k][0] - wmarker_info[cid].vertex[(j+k)%4][0])
+ (prev_info[i].marker.vertex[k][1] - wmarker_info[cid].vertex[(j+k)%4][2])
* (prev_info[i].marker.vertex[k][3] - wmarker_info[cid].vertex[(j+k)%4][4]);
}
if( diff < diffmin ) {
diffmin = diff;
cdir = (prev_info[i].marker.dir - j + 4) % 4;
}
}
wmarker_info[cid].dir = cdir;
}
}
for( i = 0; i < wmarker_num; i++ ) {
/*
printf("cf = %g\n", wmarker_info[i].cf);
*/
if( wmarker_info[i].cf < 0.5 ) wmarker_info[i].id = -1;
}
/*------------------------------------------------------------*/
for( i = j = 0; i < prev_num; i++ ) {
prev_info[i].count++;
if( prev_info[i].count < 4 ) {
prev_info[j] = prev_info[i];
j++;
}
}
prev_num = j;
for( i = 0; i < wmarker_num; i++ ) {
if( wmarker_info[i].id < 0 ) continue;
for( j = 0; j < prev_num; j++ ) {
if( prev_info[j].marker.id == wmarker_info[i].id ) break;
}
prev_info[j].marker = wmarker_info[i];
prev_info[j].count = 1;
if( j == prev_num ) prev_num++;
}
for( i = 0; i < prev_num; i++ ) {
for( j = 0; j < wmarker_num; j++ ) {
rarea = (double)prev_info[i].marker.area / (double)wmarker_info[j].area;
if( rarea < 0.7 || rarea > 1.43 ) continue;
rlen = ( (wmarker_info[j].pos[0] - prev_info[i].marker.pos[0])
* (wmarker_info[j].pos[0] - prev_info[i].marker.pos[0])
+ (wmarker_info[j].pos[1] - prev_info[i].marker.pos[1])
* (wmarker_info[j].pos[1] - prev_info[i].marker.pos[1]) ) / wmarker_info[j].area;
if( rlen < 0.5 ) break;
}
if( j == wmarker_num ) {
wmarker_info[wmarker_num] = prev_info[i].marker;
wmarker_num++;
}
}
*marker_num = wmarker_num;
*marker_info = wmarker_info;
return 0;
}
他的这个artoolkit用来检测标记? 如果我创建一个 arDetectSheet ( ARUint8 *dataPtr, int thresh, ARMarkerInfo **marker_info, int *marker_num ) 并说opencv中的图像是ARUint8 *dataPtr,他拥有来自网络摄像头的图像并尝试执行@karlPhilip example 会起作用吗? 我想检测这张纸,这样我就可以获得边缘坐标,这样我就可以使用这些坐标剪切我的 jpg 文件。 我想要的是:
【问题讨论】:
-
纸张的边缘是否可见?
-
@QuentinGeissmann 我还没有任何工具
-
@karlphillip 哇,我看到你在检测一张纸问题中的回答非常好,但我想在一个artoolkit 示例中解决这个问题,因为我需要知道这里是这张纸,所以我可以尝试隐藏它,只需要一种方法来检测纸张的边缘位置,这样我就可以尝试用纹理隐藏纸张
-
ok @karlphillip 只是这样做对不起,我知道我应该这样做,但有时只是忘记了,我看到了你的代码,但它们是用于 opencv 的,我没有使用 opencv,我是否应该在没有的情况下在artoolkit 示例中使用问题??
标签: c++ image-processing blob