OpenCV C++ - 具有不规则边的矩形检测

Question

嗨..我遇到了矩形检测的问题，它有不规则的边（不是直的），如上图。实际上使用 houghline 方法可以通过一些参数配置来检测矩形上的线条。计算相交并得到4个角后，我可以将其旋转到正常位置。

但是如果我用另一个矩形（不同大小并且仍然有不规则边）更改图像，我需要重新配置参数。这是因为四边都没有检测到线，而且线可以多于4。

除了houghline还有其他更简单（不需要重新配置/困难配置）的方法吗？

Answer 1

这种方法是计算包含所有矩形像素的旋转矩形。

也许您可以将其与 vasanth 的答案结合起来，因此您可以先近似多项式以获得规则边框，然后使用 cv::minAreaRect 提取旋转矩形

这是我的代码：

int main()
{
    cv::Mat input = cv::imread("../inputData/RotatedRect.png");

    // convert to grayscale (you could load as grayscale instead)
    cv::Mat gray;
    cv::cvtColor(input,gray, CV_BGR2GRAY);

    // compute mask (you could use a simple threshold if the image is always as good as the one you provided)
    cv::Mat mask;
    cv::threshold(gray, mask, 0, 255, CV_THRESH_BINARY_INV | CV_THRESH_OTSU);

    // find contours (if always so easy to segment as your image, you could just add the black/rect pixels to a vector)
    std::vector<std::vector<cv::Point>> contours;
    std::vector<cv::Vec4i> hierarchy;
    cv::findContours(mask,contours, CV_RETR_EXTERNAL, CV_CHAIN_APPROX_SIMPLE);

    /// Draw contours and find biggest contour (if there are other contours in the image, we assume the biggest one is the desired rect)
    // drawing here is only for demonstration!
    int biggestContourIdx = -1;
    float biggestContourArea = 0;
    cv::Mat drawing = cv::Mat::zeros( mask.size(), CV_8UC3 );
    for( int i = 0; i< contours.size(); i++ )
    {
        cv::Scalar color = cv::Scalar(0, 100, 0);
        drawContours( drawing, contours, i, color, 1, 8, hierarchy, 0, cv::Point() );

        float ctArea= cv::contourArea(contours[i]);
        if(ctArea > biggestContourArea)
        {
            biggestContourArea = ctArea;
            biggestContourIdx = i;
        }
    }

    // if no contour found
    if(biggestContourIdx < 0)
    {
        std::cout << "no contour found" << std::endl;
        return 1;
    }

    // compute the rotated bounding rect of the biggest contour! (this is the part that does what you want/need)
    cv::RotatedRect boundingBox = cv::minAreaRect(contours[biggestContourIdx]);
    // one thing to remark: this will compute the OUTER boundary box, so maybe you have to erode/dilate if you want something between the ragged lines



    // draw the rotated rect
    cv::Point2f corners[4];
    boundingBox.points(corners);
    cv::line(drawing, corners[0], corners[1], cv::Scalar(255,255,255));
    cv::line(drawing, corners[1], corners[2], cv::Scalar(255,255,255));
    cv::line(drawing, corners[2], corners[3], cv::Scalar(255,255,255));
    cv::line(drawing, corners[3], corners[0], cv::Scalar(255,255,255));

    // display
    cv::imshow("input", input);
    cv::imshow("drawing", drawing);
    cv::waitKey(0);

    cv::imwrite("rotatedRect.png",drawing);

    return 0;
}

给出这个结果：

Answer 2

试试这个：

1.在图片上运行findCountours。

2.应用approxPolyDP 将轮廓近似为矩形。轮廓边会更加规则。

3.使用moments 和/或几何分割矩形轮廓。

Answer 3

使用初等几何， 你需要找到坐标在哪里

• x 坐标最小的黑色像素位置
• x 坐标最大的黑色像素位置
• y 坐标最小的黑色像素位置
• y 坐标最大的黑色像素位置

这 4 个点将成为矩形的边缘。