如何将两个不同的哈希数组中的值相加？

Question

我有两个哈希数组。哈希的键不同：

player_scores1 = [{:first_name=>"Bruce", :score => 43, :time => 50},
                  {:first_name=>"Clark", :score => 45, :minutes => 20}]

player_scores2 = [{:last_name=>"Wayne", :points => 13, :time => 40},
                  {:last_name=>"Kent", :points => 3, :minutes => 20}]

我想创建一个新的哈希数组，将 :score 和 :points 加起来，并将其分配给一个名为 :score 的键。我还想组合 :first_name 和 :last_name 并将其分配给一个名为 :full_name 的键。我想丢弃任何其他键。

这将导致这个数组：

all_players = [{:full_name => "Bruce Wayne", :score => 56}, 
               {:full_name => "Clark Kent", :score => 48}]

有没有优雅的方法来做到这一点？

Answer 1

类似这样的：

player_scores1.zip(player_scores2).map { |a,b|
    {
        :full_name => a[:first_name]+' '+b[:last_name],
        :score => a[:score]+b[:points]
    }
}

Answer 2

您要查找的代码是：

final = []
player_scores1.each_index do |index|
  entry_1 = player_scores1.values(index)
  entry_2 = player_scores2.values(index)[:first_name]
  score = entry_1[:score] + entry_2[:points]
  final << {:full_name => "#{entry_1[:first_name]} #{entry_2[:last_name]}", :score => score }
end

任何关于加强这一点的建议将不胜感激！

Answer 3

这行得通。不过，如果这足够优雅，我不会。

player_scores1 = [{:first_name=>"Bruce", :score => 43, :time => 50},
                  {:first_name=>"Clark", :score => 45, :minutes => 20}]

player_scores2 = [{:last_name=>"Wayne", :points => 13, :time => 40},
                  {:last_name=>"Kent", :points => 3, :minutes => 20}]

p (0...[player_scores1.length, player_scores2.length].min).map {|i| {
    :full_name => player_scores1[i][:first_name] + " " + player_scores2[i][:last_name], 
    :score => player_scores1[i][:score] + player_scores2[i][:points]
}}

Codepad 上的这个例子。

Answer 4

这使用 zip 和一个块来循环哈希，连接名称并总结：

all_players = []
player_scores1.zip(player_scores2) { |a, b| 
  all_players << { 
    :full_name => a[:first_name] + ' ' + b[:last_name],
    :score     => a[:score] + b[:points]
  } 
}
all_players # => [{:full_name=>"Bruce Wayne", :score=>56}, {:full_name=>"Clark Kent", :score=>48}]