删除两个嵌套多维数组的重复值

Question

我正在努力使用 array_diff 函数和解决我的问题的另一种解决方案，但没有什么能给我想要的效果..

我有两个从数据库返回的多维数组（嵌套深度未知），并将编码和解码为 JSON。

数组如下所示：

Array ( 
    [0] => Array ( [id] => 1 [lft] => 1  [rgt] => 2  ) 
    [1] => Array ( [id] => 2 [lft] => 3  [rgt] => 4  )
    [2] => Array ( [id] => 3 [lft] => 5  [rgt] => 6  )
    [3] => Array ( [id] => 4 [lft] => 7  [rgt] => 16 )
    [4] => Array ( [id] => 5 [lft] => 8  [rgt] => 9  )
    [5] => Array ( [id] => 6 [lft] => 10 [rgt] => 11 )
    [6] => Array ( [id] => 7 [lft] => 12 [rgt] => 15 )
    [7] => Array ( [id] => 8 [lft] => 13 [rgt] => 14 )
    [8] => Array ( [id] => 9 [lft] => 17 [rgt] => 18 )
)

Array ( 
    [0] => Array ( [id] => 17 [lft] => 1 [rgt] => 2  ) 
    [1] => Array ( [id] => 3  [lft] => 3 [rgt] => 10 )
    [2] => Array ( [id] => 9  [lft] => 4 [rgt] => 9  )
    [3] => Array ( [id] => 24 [lft] => 5 [rgt] => 6  )
    [4] => Array ( [id] => 81 [lft] => 7 [rgt] => 8  )
)

现在我想合并这两个数组，以便我得到第一个数组，其中没有与第二个数组中的元素具有相同 id 的元素。 结果应该是这样的：

Array ( 
    [0] => Array ( [id] => 1 [lft] => 1  [rgt] => 2  ) 
    [1] => Array ( [id] => 2 [lft] => 3  [rgt] => 4  )
    [3] => Array ( [id] => 4 [lft] => 7  [rgt] => 16 )
    [4] => Array ( [id] => 5 [lft] => 8  [rgt] => 9  )
    [5] => Array ( [id] => 6 [lft] => 10 [rgt] => 11 )
    [6] => Array ( [id] => 7 [lft] => 12 [rgt] => 15 )
    [7] => Array ( [id] => 8 [lft] => 13 [rgt] => 14 )
)

例如，我尝试过使用 this 修改函数的其他解决方案方法，但似乎没有任何效果。有人可以帮帮我吗？

Answer 1

你说得对，你需要array_udiff。

试试这个：

$res = array_udiff($array1, $array2, function ($a, $b) {
    if ($a['id'] < $b['id']) {
        return -1;
    } elseif ($a['id'] > $b['id']) {
        return 1;
    } else {
        return 0;
    }
});