【发布时间】:2018-02-04 00:52:20
【问题描述】:
总的来说,我对 iOS 开发比较陌生,但我正在编写这个应用程序。
我有自定义对象“学期”、“课程”和“作业”。学期包含课程数组,课程包含作业数组。我能够正确存档学期和课程信息,但由于某种原因无法读取作业信息。
学期:
required init?(coder aDecoder: NSCoder) {
self.name = ""
super.init()
if let archivedName = aDecoder.decodeObject(forKey: "name") as? String {
name = archivedName
}
if let archivedCourses = aDecoder.decodeObject(forKey: "courses") as? [Course] {
courses = archivedCourses
}
}
func encode(with aCoder: NSCoder) {
aCoder.encode(name, forKey: "name")
aCoder.encode(courses, forKey: "courses")
}
课程:
required init?(coder aDecoder: NSCoder) {
self.name = ""
super.init()
if let archivedName = aDecoder.decodeObject(forKey: "courseName") as? String {
name = archivedName
}
if let archivedAssignments = aDecoder.decodeObject(forKey: "assignments") as? [Assignment] {
assignments = archivedAssignments
}
}
func encode(with aCoder: NSCoder) {
aCoder.encode(name, forKey: "courseName")
aCoder.encode(assignments, forKey: "assignments")
作业:
required init?(coder aDecoder: NSCoder) {
self.name = ""
self.grade = 0
self.weight = 0
super.init()
if let archivedName = aDecoder.decodeObject(forKey: "assignmentName") as? String, let archivedGrade = aDecoder.decodeObject(forKey: "assignmentGrade") as? Int, let archivedWeight = aDecoder.decodeObject(forKey: "assignmentWeight") as? Int {
name = archivedName
grade = archivedGrade
weight = archivedWeight
}
}
func encode(with aCoder: NSCoder) {
aCoder.encode(name, forKey: "assignmentName")
aCoder.encode(grade, forKey: "assignmentGrade")
aCoder.encode(weight, forKey: "assignmentWeight")
}
我不知道为什么,但是当我尝试解码对象时无法读取分配详细信息。
【问题讨论】:
-
decoderObject 有一个特殊的方法来解码 Ints
-
我的回答对您有帮助吗?感谢任何反馈,谢谢
-
是的!谢谢你的帮助!!
-
那你能接受我的回答吗?是灰色复选标记谢谢
-
完成!抱歉,刚加入网站。
标签: ios swift archive nscoding