计算数组中的重复键并将它们相加

Question

我正在尝试遍历已确定论坛主题的所有页面并获取每个用户的帖子总数，但我很难理解每次用户名在数组中重复时如何求和。

这是我的代码：

for ($x = 1; $x <= 5; $x++) {

    $ch = curl_init('http://myforum.com/thread-123?&page=' . $x);

    curl_setopt_array($ch, array(
        CURLOPT_HEADER => TRUE,
        CURLOPT_RETURNTRANSFER => TRUE
    ));

    $response = curl_exec($ch);

    preg_match_all('/me\">[\s]+<a href=\"([^\"]+)\">([^<]+)/i', $response, $users);
    preg_match_all('/image_avatar\" src=\"([^\"]+)"/i', $response, $avatar);


    $q = count($users[1]);

    for ($i = 0; $i < $q; $i++) {
        ///////count how many times the user was inside the array///////
        //$totalPosts = ?
        ///////count how many times the user was inside the array///////

        print '-----<br /><img src="'.$avatar[1][$i].'" /><br />User: ' . $users[2][$i] . '<br />Total Posts: ' . $totalPosts . '-----<br />';        

    }


}

解决方案，谢谢@u_mulder

$all_users = array();
for ($x = 1; $x <= 5; $x++) {

    $ch = curl_init('http://myforum.com/thread-123?&page=' . $x);

    curl_setopt_array($ch, array(
        CURLOPT_HEADER => TRUE,
        CURLOPT_RETURNTRANSFER => TRUE
    ));

    $response = curl_exec($ch);

    preg_match_all('/me\">[\s]+<a href=\"([^\"]+)\">([^<]+)/i', $response, $users);
    preg_match_all('/image_avatar\" src=\"([^\"]+)"/i', $response, $avatar);


    $all_users = array_merge($all_users, $users[2]);


}
function aprint($arr, $return = false) {
    arsort($arr);
    $wrap = '<div style=" white-space:pre; position:absolute; top:10px; left:10px; height:200px; width:100px; overflow:auto; z-index:5000;">';
    $wrap = '<pre>';
    $txt = preg_replace('/(\[.+\])\s+=>\s+Array\s+\(/msiU','$1 => Array (', print_r($arr,true));

    if ($return) return  $wrap.$txt.'</pre>';
    else echo $wrap.$txt.'</pre>';
}

$res = array_icount_values ($all_users);
$res2 = aprint($res);
print_r($res2); 

function array_icount_values($arr,$lower=true) { 
     $arr2=array(); 
     if(!is_array($arr['0'])){$arr=array($arr);} 
     foreach($arr as $k=> $v){ 
      foreach($v as $v2){ 
      if($lower==true) {$v2=strtolower($v2);} 
      if(!isset($arr2[$v2])){ 
          $arr2[$v2]=1; 
      }else{ 
           $arr2[$v2]++; 
           } 
    } 
    } 
    return $arr2; 
}

示例输出（用户名 => 帖子总数）也按帖子总数排序：

Array
(
    [user 1] => 35
    [user 2] => 11
    [user 3] => 11
    [user 4] => 8
    [user 5] => 5
    [user 6] => 4
    [user 7] => 3
    [user 8] => 2
    [user 9] => 2
    [user 10] => 2
    [user 11] => 2
    [user 12] => 1
    [user 13] => 1
    [user 14] => 1
    [user 15] => 1
    [user 16] => 1
    [user 17] => 1
    [user 18] => 1
    [user 19] => 1
    [user 20] => 1
    [user 21] => 1
    [user 22] => 1
    [user 23] => 1
    [user 24] => 1
    [user 25] => 1
    [user 26] => 1
)

Answer 1

要计算数组中项目的频率，您可以使用array_count_values 函数。

您提供的数组代码作为示例：

$users = array('user found 1', 'user found 2', 'user found 3', 'user found 1', 'user found 2', 'user found 1', 'user found 1');
print_r(array_count_values($users));

结果是：

Array ( [user found 1] => 4 [user found 2] => 2 [user found 3] => 1 ) 

更新 好的，如果您有不同的页面，请尝试以下操作：

$all_users = array();
for ($x = 1; $x <= 5; $x++) {
    // ....
    preg_match_all('/me\">[\s]+<a href=\"([^\"]+)\">([^<]+)/i', $response, $users);

    $all_users = array_merge($all_users, $users[1]);
}
print_r(array_count_values($all_users));