来自 SELECT 的更新：加入方法 [关闭]

Question

我正在使用这个

UPDATE stockout_details
SET 
stockout_details.chaloutinv=stockin_details.inv_cha
FROM stockout_details 
INNER JOIN stockin_details
ON stockin_details.marka = stockout_details.marka and stockin_details.purchi = stockout_details.purchi and 
stockin_details.chalan = stockout_details.chalan and stockin_details.room = stockout_details.room and
stockin_details.rack = stockout_details.rack 

错误是

UPDATE stockout_details
SET 
stockout_details.chaloutinv=stockin_details.inv_cha
FROM stockout_details 
INNER JOIN
'stockin_details'
ON stockin_details.marka = stockout_details.marka and stockin_details.purchi = stockout_details.purchi and 
stockin_details.chalan = stockout_details.chalan and stockin_details.room = stockout_details.room and
stockin_details.rack = stockout_details.rack;

MySQL 说：文档

#1064 - 您的 SQL 语法有错误；检查与您的 MariaDB 服务器版本相对应的手册，以在“FROM stockout_details
附近使用正确的语法 内连接
'stockin_details'
ON stockin_details.mar...' 在第 4 行

Answer 1

使用 JOIN 进行更新应如下所示：

UPDATE T1,T2
INNER JOIN T2 ON T1.C1 = T2.C1
SET T1.C2 = T2.C2,
      T2.C3 = expr
WHERE condition

所以你不需要添加FROM table