删除空 JSON 参数 [重复]

Question

我已经设置了一个变量列表及其值：

$exp = "1642873358";
$country_code = "LO";
$item_description = "An item";
$language_code = "";
$price_amount = "5.99";
$price_currency = "EUR";
$urls_authorisation_callback = "https://www.example.com/";
$urls_redirect = "https://www.example.com/";
$urls_unsubscription_redirect = "";
$subscription_duration = "";
$subscription_unit = "";
$subscription_cycles = "";
$subscription_price_amount = "";
$subscription_price_currency = "";
$msisdn = "55555555";
$msisdn_edit_disabled = "";

这些变量值应该是可编辑的，如果愿意，可以将其留空，如示例中所示。我不想删除变量。

然后我创建了一个数组，该数组后来被编码为 JSON：

$token = array(
    'exp' => "$exp" ,
    'country_code' => "$country_code",
    'item_description' => "$item_description",
    'language_code' => "$language_code",
    'price' => array(
        'amount' => "$price_amount",
        'currency' => "$price_currency" 
    ),
    'urls' => array(
        'authorisation_callback' => "$urls_authorisation_callback",
        'redirect' => "$urls_redirect",
        'unsubscription_redirect' => "$urls_unsubscription_redirect"
    ),
    'subscription' => array(
        'duration' => "$subscription_duration",
        'unit' => "$subscription_unit" ,
        'cycles' => "$subscription_cycles" ,
        'price' => array(
            'amount' => "$subscription_price_amount",
            'currency' => "$subscription_price_currency"
        )
    ),
    'msisdn' => "$msisdn",
    'msisdn_edit_disabled' => "$msisdn_edit_disabled"
);

当我最终回显 JSON 文本时：

echo json_encode($token, JSON_PRETTY_PRINT) . "\n";

我得到以下信息：

{
    "exp": "1642873358",
    "country_code": "LO",
    "item_description": "An item",
    "language_code": "",
    "price": {
        "amount": "5.99",
        "currency": "EUR"
    },
    "urls": {
        "authorisation_callback": "https:\/\/www.example.com\/",
        "redirect": "https:\/\/www.example.com\/",
        "unsubscription_redirect": ""
    },
    "subscription": {
        "duration": "",
        "unit": "",
        "cycles": "",
        "price": {
            "amount": "",
            "currency": ""
        }
    },
    "msisdn": "55555555",
    "msisdn_edit_disabled": ""
}

如果我想删除未指定值的参数，我有哪些选择？以一种不会弄乱所需 JSON 结构的方式。给定示例中的期望结果是：

{
    "exp": "1642873358",
    "country_code": "LO",
    "item_description": "An item",
    "price": {
        "amount": "5.99",
        "currency": "EUR"
    },
    "urls": {
        "authorisation_callback": "https:\/\/www.example.com\/",
        "redirect": "https:\/\/www.example.com\/"
    },
    "msisdn": "55555555"
}

Answer 1

将其转换为数组。使用 json_decode

然后使用下面的递归函数删除空值。然后再次编码为 json。

function array_remove_empty($haystack)
{
    foreach ($haystack as $key => $value) {
        if (is_array($value)) {
            $haystack[$key] = array_remove_empty($haystack[$key]);
        }

        if (empty($haystack[$key])) {
            unset($haystack[$key]);
        }
    }

    return $haystack;
}

$token = array_remove_empty($token);