【发布时间】：2015-09-24 10:15:40
【问题描述】：
通过 REST API for Twitter 的视频上传功能在 1 月可用，但在 Fabric 框架中不可用： link!
【问题讨论】：
-
如果你有多个segment，你可以试试这个解决方案：stackoverflow.com/a/48563257/3894440
标签： ios objective-c video twitter twitter-fabric
【发布时间】：2015-09-24 10:15:40
【问题描述】：
根据documentation 需要使用以下命令进行 3 次调用：INIT、APPEND 和 FINALIZE。
-(void) shareOnTwitterWithVideo:(NSDictionary*) params{
NSString *text = params[@"text"];
NSData* dataVideo = params[@"video"];
NSString *lengthVideo = [NSString stringWithFormat:@"%d", [params[@"length"] intValue]];
NSString* url = @"https://upload.twitter.com/1.1/media/upload.json";
__block NSString *mediaID;
if([[Twitter sharedInstance] session]){
TWTRAPIClient *client = [[Twitter sharedInstance] APIClient];
NSError *error;
// First call with command INIT
NSDictionary *message = @{ @"status":text,
@"command":@"INIT",
@"media_type":@"video/mp4",
@"total_bytes":lengthVideo};
NSURLRequest *preparedRequest = [client URLRequestWithMethod:@"POST" URL:url parameters:message error:&error];
[client sendTwitterRequest:preparedRequest completion:^(NSURLResponse *urlResponse, NSData *responseData, NSError *error){
if(!error){
NSError *jsonError;
NSDictionary *json = [NSJSONSerialization
JSONObjectWithData:responseData
options:0
error:&jsonError];
mediaID = [json objectForKey:@"media_id_string"];
client = [[Twitter sharedInstance] APIClient];
NSError *error;
NSString *videoString = [dataVideo base64EncodedStringWithOptions:0];
// Second call with command APPEND
message = @{@"command" : @"APPEND",
@"media_id" : mediaID,
@"segment_index" : @"0",
@"media" : videoString};
NSURLRequest *preparedRequest = [client URLRequestWithMethod:@"POST" URL:url parameters:message error:&error];
[client sendTwitterRequest:preparedRequest completion:^(NSURLResponse *urlResponse, NSData *responseData, NSError *error){
if(!error){
client = [[Twitter sharedInstance] APIClient];
NSError *error;
// Third call with command FINALIZE
message = @{@"command" : @"FINALIZE",
@"media_id" : mediaID};
NSURLRequest *preparedRequest = [client URLRequestWithMethod:@"POST" URL:url parameters:message error:&error];
[client sendTwitterRequest:preparedRequest completion:^(NSURLResponse *urlResponse, NSData *responseData, NSError *error){
if(!error){
client = [[Twitter sharedInstance] APIClient];
NSError *error;
// publish video with status
NSString *url = @"https://api.twitter.com/1.1/statuses/update.json";
NSMutableDictionary *message = [[NSMutableDictionary alloc] initWithObjectsAndKeys:text,@"status",@"true",@"wrap_links",mediaID, @"media_ids", nil];
NSURLRequest *preparedRequest = [client URLRequestWithMethod:@"POST" URL:url parameters:message error:&error];
[client sendTwitterRequest:preparedRequest completion:^(NSURLResponse *urlResponse, NSData *responseData, NSError *error){
if(!error){
NSError *jsonError;
NSDictionary *json = [NSJSONSerialization
JSONObjectWithData:responseData
options:0
error:&jsonError];
NSLog(@"%@", json);
}else{
NSLog(@"Error: %@", error);
}
}];
}else{
NSLog(@"Error command FINALIZE: %@", error);
}
}];
}else{
NSLog(@"Error command APPEND: %@", error);
}
}];
}else{
NSLog(@"Error command INIT: %@", error);
}
}];
}
}
【讨论】：
-
感谢@fechidal 提供简洁和最新的答案！
-
@fechidal：太棒了.. 效果很好！可惜推特自己没有这个。
-
我在 APPEND 上遇到错误 ---> 错误域=TWTRNetworkingErrorDomain 代码=-1011 “请求失败：错误请求 (400)”。有什么想法可以解决这个问题吗？
-
@John81 你确定收到一个 mediaID 吗？ videoString 是您的 NSData 视频转换为基于 64 的字符串，您确定吗？
-
@fechidal 是的，我确实从 INIT 响应中获得了 mediaID -> 响应：{ "expires_after_secs" = 86399; “media_id”=660168523088433152； "media_id_string" = 660168523088433152; }，视频数据看起来也被正确转换为字符串。我希望我收到更具描述性的错误消息。
很好的答案，把它转换成 swift 很有趣，花了我一段时间，所以这里是为其他有同样问题的人准备的：
var video: NSData!
let strUploadUrl = "https://upload.twitter.com/1.1/media/upload.json"
let strStatusUrl = "https://api.twitter.com/1.1/statuses/update.json"
func postVideo() {
var client = Twitter.sharedInstance().APIClient
var text: String = "Testing Video"
var videoLength: String = "\(self.video.length)"
var mediaID: String = ""
var initError: NSError?
var message = ["status": text, "command" : "INIT", "media_type" : "video/m4v", "total_bytes" : videoLength]
var preparedRequest: NSURLRequest = client.URLRequestWithMethod("POST", URL: self.strUploadUrl, parameters: message, error: &initError)
client.sendTwitterRequest(preparedRequest, completion: { (urlResponse: NSURLResponse?, responseData: NSData?, error: NSError?) -> Void in
if error == nil {
var jsonError: NSError?
var json: NSDictionary = (NSJSONSerialization.JSONObjectWithData(responseData!, options: nil, error: &jsonError) as? NSDictionary)!
println(json)
var mediaID = json.objectForKey("media_id_string") as! String
client = Twitter.sharedInstance().APIClient
var uploadError: NSError?
var videoString = self.video.base64EncodedStringWithOptions(nil)
message = ["command" : "APPEND", "media_id" : mediaID, "segment_index" : "0", "media" : videoString]
var preparedRequest = client.URLRequestWithMethod("POST", URL: self.strUploadUrl, parameters: message, error: &uploadError)
client.sendTwitterRequest(preparedRequest, completion: { (urlResponse: NSURLResponse?, responseData: NSData?, error: NSError?) -> Void in
if error == nil {
client = Twitter.sharedInstance().APIClient
var finalizeError: NSError?
message = ["command":"FINALIZE", "media_id": mediaID]
var preparedRequest = client.URLRequestWithMethod("POST", URL: self.strUploadUrl, parameters: message, error: &finalizeError)
client.sendTwitterRequest(preparedRequest, completion: { (urlResponse: NSURLResponse?, responseData: NSData?, error: NSError?) -> Void in
if error == nil {
client = Twitter.sharedInstance().APIClient
var sendError: NSError?
var message = ["status": text, "wrap_links": "true", "media_ids": mediaID]
var updateMessage = NSMutableDictionary(dictionary: message)
var preparedRequest = client.URLRequestWithMethod("POST", URL: self.strStatusUrl, parameters: message , error: &sendError)
client.sendTwitterRequest(preparedRequest, completion: { (urlResponse: NSURLResponse?, responseData: NSData?, error: NSError?) -> Void in
})
} else {
println("Command FINALIZE failed \n \(error!)")
}
})
} else {
println("Command APPEND failed")
}
})
} else {
println("Command INIT failed")
}
})
}
【讨论】：
-
@Swinny89 我已经实现了和你的一样但是返回“命令追加失败”我不知道我做错了什么？请帮我解决。
-
在
println("Command APPEND failed")之前添加println(error)让您更清楚地了解请求失败的原因 -
@Swinny89 抛出这样的错误“请求失败：未经授权（401）” UserInfo=0x7f9d00d61fc0 {NSErrorFailingURLKey=upload.twitter.com/1.1/media/upload.json，NSLocalizedDescription=请求失败：未经授权（401），NSLocalizedFailureReason=Twitter API 错误： 无法验证您的身份。 (代码 32)})"
-
此解决方案不再起作用。您有最新的解决方案吗？我没有收到我的帖子的答案：stackoverflow.com/questions/36248965/… 也没有找到 swift 2 的任何相关解决方案