如何使用 xslt 将元素列表类型的 xml 重构为元素

Question

我有一个从 JSON 到 XML 转换的以下格式的 XML。

完整的原始 XML 示例：

示例 1：

<?xml version="1.0" encoding="UTF-8"?>
<linked-hash-map>
   <entry>
      <string>dataset</string>
      <linked-hash-map>
         <entry>
            <string>id</string>
            <string>120140</string>
         </entry>
         <entry>
            <string>dataset_code</string>
            <string>GDP</string>
         </entry>
         <entry>
            <string>column_names</string>
            <list>
               <string>DATE</string>
               <string>VALUE</string>
            </list>
         </entry>
         <entry>
            <string>frequency</string>
            <string>quarterly</string>
         </entry>
         <entry>
            <string>type</string>
            <string>Time Series</string>
         </entry>
         <entry>
            <string>premium</string>
            <boolean>false</boolean>
         </entry>
         <entry>
            <string>data</string>
            <list>
               <list>
                  <string>2016-07-01</string>
                  <double>18675.3</double>
               </list>
               <list>
                  <string>2016-04-01</string>
                  <double>18450.1</double>
               </list>
               <list>
                  <string>2016-01-01</string>
                  <double>18281.6</double>
               </list>
            </list>
         </entry>
         <entry>
            <string>database_id</string>
            <int>118</int>
         </entry>
      </linked-hash-map>
   </entry>
</linked-hash-map>

示例 2：

<?xml version="1.0" encoding="UTF-8"?>
<linked-hash-map>
   <entry>
      <string>dataset</string>
      <linked-hash-map>
         <entry>
            <string>dataset_code</string>
            <string>AAPL</string>
         </entry>
         <entry>
            <string>column_names</string>
            <list>
               <string>DATE</string>
               <string>Open</string>
               <string>High</string>
               <string>Low</string>
               <string>Close</string>
            </list>
         </entry>
         <entry>
            <string>frequency</string>
            <string>quarterly</string>
         </entry>
         <entry>
            <string>type</string>
            <string>Time Series</string>
         </entry>
         <entry>
            <string>data</string>
            <list>
               <list>
                  <string>2016-07-01</string>
                  <double>116.45</double>
                  <double>117.1095</double>
                  <double>116.4</double>
                  <double>116.73</double>
               </list>
               <list>
                  <string>2016-04-01</string>
                  <double>18450.1</double>
                  <double>113.1095</double>
                  <double>112.4</double>
                  <double>100.73</double>
               </list>
               <list>
                  <string>2016-01-01</string>
                  <double>18281.6</double>
                  <double>157.1095</double>
                  <double>136.4</double>
                  <double>156.73</double>
               </list>
            </list>
         </entry>
         <entry>
            <string>database_id</string>
            <int>218</int>
         </entry>
      </linked-hash-map>
   </entry>
</linked-hash-map>

以下部分需要在两个xml中进行转换。

<entry>
       <string>column_names</string>
        <list>
          <string>DATE</string>
          <string>VALUE</string>
        </list>
</entry>
     <entry>
            <string>data</string>
            <list>
              <list>
                <string>2016-07-01</string>
                <double>18675.3</double>
              </list>
              <list>
                <string>2016-04-01</string>
                <double>18450.1</double>
              </list>
             </list>
    </entry>

如何将其转换为以下格式？

1.

  <entry>
       <Date>2016-07-01</Date>
            <Value>18675.3</Value>
        </entry>
        <entry>
            <Date>2016-04-01</Date>
            <Value>18450.1</Value>
         </entry>

2.

<entry>
    <Date>2016-07-01</Date>
    <Value>18675.3</Value>
    <Date>2016-04-01</Date>
    <Value>18450.1</Value>
    </entry>

注意：这里的所有数据（日期、值、数据、条目等）都是动态的。

寻找 XSLT 的通用实现以带来所需的输出。如果不能用 xslt，那么想去 Java 来转换它。

任何帮助将不胜感激。``

Answer 1

以下样式表适用于您的两个示例。我认为它不需要比这更通用 - 如果是，我不知道如何。

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:template match="/linked-hash-map">
    <xsl:variable name="col-names" select="entry/linked-hash-map/entry[string='column_names']/list/string" />
    <root>
        <xsl:for-each select="entry/linked-hash-map/entry[string='data']/list/list">
            <xsl:variable name="current-row" select="." />
            <entry>
                <xsl:for-each select="$col-names">
                    <xsl:variable name="i" select="position()" />
                    <xsl:element name="{.}">
                        <xsl:value-of select="$current-row/*[$i]" />
                    </xsl:element>
                </xsl:for-each>
            </entry>
        </xsl:for-each>
    </root>
</xsl:template>

</xsl:stylesheet>

与your previous question 一样，这假定提供的列名是有效的 XML 元素名。