【发布时间】:2015-07-23 05:00:53
【问题描述】:
我是 python 新手,我正在创建一个程序来检查所需用户输入的用户名和密码是否存在于数据库中。这是代码:
import mysql.connector
class data:
def __init__(self):
self.usernam = input("Enter user name: ")
self.password= input("Enter Password: ")
a=data()
conn = mysql.connector.connect(host='localhost',user='root',passwd='root',database='user')
loadname= ("select username from user where username='%s'")
mycursor=conn.cursor()
mycursor.execute(a.usernam, loadname)
usercheck=mycursor.fetchone()
loadpass= ("select pass from user where pass ='%s'")
mycursor2=conncursor()
mycursor2.execute(a.password,loadpass)
passcheck=mycursor2.fetchone()
if a.username == usercheck and a.password == passcheck:
print ("pass")
else:
print ("sorry")
conn.commit()
conn.close()
我收到以下错误:
Traceback (most recent call last):
File "C:\Users\HP\Desktop\2nd.py", line 16, in <module>
mycursor.execute(a.usernam, loadname)
File "C:\Python34\lib\site-packages\mysql\connector\cursor.py", line 507, in execute
self._handle_result(self._connection.cmd_query(stmt))
File "C:\Python34\lib\site-packages\mysql\connector\connection.py", line 722, in cmd_query
result = self._handle_result(self._send_cmd(ServerCmd.QUERY, query))
File "C:\Python34\lib\site-packages\mysql\connector\connection.py", line 640, in _handle_result
raise errors.get_exception(packet)
mysql.connector.errors.ProgrammingError: 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'asaa' at line 1
【问题讨论】:
-
asaaanywhere 在哪里,必须是入口用户名? -
是用户输入的用户名。 (顺便说一句,这个 'asaa' 用户名存在于 mysql 表的用户名列中)