【问题标题】:Rectangle using CLLocationCoordinate2D使用 CLLocationCoordinate2D 的矩形
【发布时间】:2020-06-22 16:20:40
【问题描述】:
我想知道我是否可以使用左上角和右下角CLLocationCoordinate2D 创建一个矩形,然后通过检查(topLeftCoordinate.latitude < coordinate.latitude && bottomRightCoordinate.latitude > coordinate.latitude) && (topLeftCoordinate.longitude < coordinate.longitude && bottomRightCoordinate.longitude > coordinate.longitude) 来检查一个坐标是否是这个矩形的一部分。
我认为坐标将代表球体上的一个点,然后这行不通。但是由于CLLocationCoordinate2D 末尾的2D,我感到困惑。有人可以澄清一下吗?
谢谢:)
【问题讨论】:
标签:
ios
swift
coordinates
core-location
【解决方案1】:
您将能够从您的坐标创建一个 MKPolygon 并使用此函数来确定坐标是否在该多边形内:
func isPoint(point: MKMapPoint, insidePolygon poly: MKPolygon) -> Bool {
let polygonVerticies = poly.points()
var isInsidePolygon = false
for i in 0..<poly.pointCount {
let vertex = polygonVerticies[i]
let nextVertex = polygonVerticies[(i + 1) % poly.pointCount]
// The vertices of the edge we are checking.
let xp0 = vertex.x
let yp0 = vertex.y
let xp1 = nextVertex.x
let yp1 = nextVertex.y
if ((yp0 <= point.y) && (yp1 > point.y) || (yp1 <= point.y) && (yp0 > point.y))
{
// If so, get the point where it crosses that line. This is a simple solution
// to a linear equation. Note that we can't get a division by zero here -
// if yp1 == yp0 then the above if be false.
let cross = (xp1 - xp0) * (point.y - yp0) / (yp1 - yp0) + xp0
// Finally check if it crosses to the left of our test point. You could equally
// do right and it should give the same result.
if cross < point.x {
isInsidePolygon = !isInsidePolygon
}
}
}
return isInsidePolygon
}