【发布时间】:2021-01-21 03:04:22
【问题描述】:
我是 Python 的初学者(有点)。在我的井字游戏中,我被困在获胜者(棋盘)功能上,因为每当我运行程序并在任何地方放置一个 X 时,它都会立即显示“Y O U W O N !”当我删除 make_computer_move(board) 下的代码以尝试调试我的获胜者(board) 函数时,从右上角到左下角的对角线不起作用,但从左上角到右下角的获胜者确定代码有效。下面是我的代码:
"""
Author: Victor Xu
Date: Jan 12, 2021
Description: An implementation of the game Tic-Tac-Toe in Python,
using a nested list, and everything else we've learned this quadmester!
"""
import random
def winner(board):
"""This function accepts the Tic-Tac-Toe board as a parameter.
If there is no winner, the function will return the empty string "".
If the user has won, it will return 'X', and if the computer has
won it will return 'O'."""
# Check rows for winner
for row in range(3):
if (board[row][0] == board[row][1] == board[row][2]) and \
(board[row][0] != " "):
return board[row][0]
# COMPLETE THE REST OF THE FUNCTION CODE BELOW
for col in range(3):
if (board[0][col] == board[1][col] == board[2][col]) and \
(board[0][col] != " "):
return board[0][col]
# Check diagonal (top-left to bottom-right) for winner
if (board[0][0] == board[1][1] == board[2][2]) and \
(board[0][0] != " "):
return board[0][0]
# Check diagonal (bottom-left to top-right) for winner
if (board[0][2] == board[1][1] == board[2][0]) and \
(board[0][0] != " "):
return board[0][0]
# No winner: return the empty string
return ""
def display_board(board):
"""This function accepts the Tic-Tac-Toe board as a parameter.
It will print the Tic-Tac-Toe board grid (using ASCII characters)
and show the positions of any X's and O's. It also displays
the column and row numbers on top and beside the board to help
the user figure out the coordinates of their next move.
This function does not return anything."""
print(" 0 1 2")
print("0: " + board[0][0] + " | " + board[0][1] + " | " + board[0][2])
print(" ---+---+---")
print("1: " + board[1][0] + " | " + board[1][1] + " | " + board[1][2])
print(" ---+---+---")
print("2: " + board[2][0] + " | " + board[2][1] + " | " + board[2][2])
print()
def make_user_move(board):
"""This function accepts the Tic-Tac-Toe board as a parameter.
It will ask the user for a row and column. If the row and
column are each within the range of 0 and 2, and that square
is not already occupied, then it will place an 'X' in that square."""
valid_move = False
while not valid_move:
row = int(input("What row would you like to move to (0-2):"))
col = int(input("What col would you like to move to (0-2):"))
if (0 <= row <= 2) and (0 <= col <= 2) and (board[row][col] == " "):
board[row][col] = 'X'
valid_move = True
else:
print("Sorry, invalid square. Please try again!\n")
def make_computer_move(board):
"""This function accepts the Tic-Tac-Toe board as a parameter.
It will randomly pick row and column values between 0 and 2.
If that square is not already occupied it will place an 'O'
in that square. Otherwise, another random row and column
will be generated."""
computer_valid_move = False
while not computer_valid_move:
row = random.randint(0, 2)
col = random.randing(0, 2)
if (0 <= row <= 2) and (0 <= col <= 2) and (board[row][col] == " "):
board[row][col] = 'O'
computer_valid_move = True
def main():
"""Our Main Game Loop:"""
free_cells = 9
users_turn = True
ttt_board = [[" ", " ", " "], [" ", " ", " "], [" ", " ", " "]]
while not winner(ttt_board) and (free_cells > 0):
display_board(ttt_board)
if users_turn:
make_user_move(ttt_board)
users_turn = not users_turn
else:
make_computer_move(ttt_board)
users_turn = not users_turn
free_cells -= 1
display_board(ttt_board)
if (winner(ttt_board) == 'X'):
print("Y O U W O N !")
elif (winner(ttt_board) == 'O'):
print("I W O N !")
else:
print("S T A L E M A T E !")
print("\n*** GAME OVER ***\n")
# Start the game!
main()
TL;DR
请查看右上角到左下角的对角线获胜确定代码以及每当我按下 X 并显示“你赢了!”时的问题
【问题讨论】:
-
通过传递性,你可以写
a == b == c != d而不是a == b == c and a != d。
标签: python