PHP使用while（mysql_fetch_array）向数组添加值？

Question

我试图在从 mysql 查询中获取数据后向数组添加值，这显然需要一段时间 ($x = mysql_fetch_array($MysqlQuery)) {}，如下所示：

      $CheckTime = mysql_query("SELECT * FROM cp11641_timetable.booking");
      $dates = array();
      while ($date = mysql_fetch_array($CheckTime)) {
        $DateInt = strtotime($date['Date']);
        //echo $DateInt . " ";
        $dates[] = $DateInt;
        echo $dates[1] . " ";
      }

但是，当我回显 $dates[x] 时，它会在数组的 x 位置显示该值，但会显示 (x+1) 次（即 $dates[0] 将显示 ' a' 一次，$dates[1] 将显示 'b' 两次，$dates[2] 将显示 'c' 三次）

我该如何解决这个问题？是什么导致了问题？

Answer 1

$CheckTime = mysqli_query($mysql_connection, "SELECT * FROM cp11641_timetable.booking");
$dates = array();
while ($date = mysqli_fetch_assoc()($CheckTime)){ // Use mysqli_* for queries.
    $DateInt = strtotime($date['Date']); // This will show an UNIX timestamp
    $dates[] = $DateInt; // Fills the array with the timestamp.
}

您的问题是您使用mysql_fetch_array。但是然后尝试使用$date['Date']。如果要将列名用作$date 数组中的索引。您需要使用mysql_fetch_assoc()。

另外，如 cmets 中所述，使用 mysqli_* 扩展名或 PDO。在这个答案中，我使用了mysqli_*

请注意 mysqli_query 函数中的$mysql_connection。 MySqli Query Doc

如果您使用下面的代码，它很可能会按预期工作。 还是强烈建议切换到mysqli_*

$CheckTime = mysql_query("SELECT Date FROM cp11641_timetable.booking");
$dates = array();
while ($date = mysql_fetch_array($CheckTime)){
    $DateInt = strtotime($date[0]);
    $dates[] = $DateInt;
}

foreach($dates as $timestamp){
    echo $timestamp . '<br/>';
}

Answer 2

这可行，请确保输入正确的凭据以在第 1 步连接到您的数据库。其他一切都是假的。

<?php 

    /* ==============================================
    This is the new way of connecting to database 
    using mysqli
    ================================================*/

    // Step #1 create credentiasl for database connection
    $host = ""; //type your host ex. localhost between the quotes
    $user = ""; //your username between the quotes
    $pass = ""; //your password between the quotes
    $db   = ""; //your database you are connecting to between the quotes

    // step #2 create connection to database
    $conn = new mysqli($host, $user, $pass, $db);

    //step #3 check and see if connection is working and error free
    if ($conn->error) {

        die("Could not connect to the database");

    } else{

        // create array dates
        $dates = array();

        // create select statement
        $CheckTime = ("SELECT * FROM cp11641_timetable.booking");

        // query the the database using the connection
        $sql_CheckTime = $conn->query($CheckTime);

        // if rows available in table add them to array dates
        while ($row = mysqli_fetch_assoc($sql_CheckTime)) {

            $dates[] = $row;

        }

        //optional uncomment bottom line to check if dates array has data will display as array on webpage
        // var_dump($dates); 

        // loop through array 
        foreach ($dates as $date){

            // echo out data you want to display. 'Date' = column name
            echo strtotime($date['Date']) . "<br>";
        };
    };

 ?>

Answer 3

我建议您使用mysql_fetch_assoc()，然后以html/css 样式水平或垂直显示日期。 对不起，如果我的回答不好，请选择。