将列转换为行 (ORACLE)答案

【问题标题】：Turning columns into rows (ORACLE)将列转换为行 (ORACLE)
【发布时间】：2015-10-03 00:32:46
【问题描述】：

我正在尝试将我的查询列转换为行。这是我的查询：

select sum(CASE WHEN 
                     t.price < 5000
                THEN t.price END) AS RANGE1,
       sum(CASE WHEN 
                     t.price between 5000 and 10000 
                THEN t.price END) AS RANGE2,
       sum(CASE WHEN 
                     t.price > 10000
                THEN t.price END) AS RANGE3
From
      cars t
Where
      t.status = 3

结果是这样的：

RANGE1   RANGE2    RANGE3
-------  -------  --------
50000     75000      84000

我想要的结果如下：

RANGE    TOTAL    
------- -------  
RANGE1   50000    
RANGE2   75000      
RANGE3   84000

【问题讨论】：

这是一个带有一些示例的线程stackoverflow.com/questions/19858079/…。

标签： oracle oracle11g

【解决方案1】：

试试：

select 
        'RANGE1' RANGE,
        sum(CASE WHEN 
                     t.price < 5000
                THEN t.price END) AS total
From
      cars t
Where
      t.status = 3 

union all

select 
        'RANGE2' RANGE,
       sum(CASE WHEN 
                     t.price between 5000 and 10000 
                THEN t.price END) AS total
From
      cars t
Where
      t.status = 3 

union all

select  
        'RANGE3' RANGE,
       sum(CASE WHEN 
                     t.price > 10000
                THEN t.price END) AS total
From
      cars t
Where
      t.status = 3

【讨论】：