输赢问题...（必须有easygui）答案

【问题标题】：Issue with Wins and Losses... (must have easygui)输赢问题...（必须有easygui）
【发布时间】：2018-03-01 12:00:19
【问题描述】：

ComputerChoice = ""
x = 0
wins = 0
losses = 0
ties = 0
rounds = 0
abc = 0
CurrentStatus = 'started'

Choices = ['Rock','Paper','Scissors']
#################################################
def computerchoice(ComputerChoice, Choices, UserChoice): #number
          listthing = Choices[:]
          #listthing.remove[UserChoice]
          ComputerChoice = random.choice(listthing)
          ComputerChoice = Choices.index(ComputerChoice)
          return ComputerChoice
#################################################
import easygui
import random
easygui.msgbox( "Hello, This is a standard game of Rock, Paper, Scissors.","Welcome!","Next>>>")

while x == 0:
         UserChoice = easygui.buttonbox(' __ __ __ __ __ __ __ __ __ __ You just ' +CurrentStatus+ '. __ __ __ __ __ __ __ __ __ __ \n You currently have won '+str(wins)+ ' times, lost ' +str(losses)+' times, and tied '+ str(ties)+' times.  \n\n\nClick your next move: ','Choice Picker 2000',['Rock','Paper','Scissors','Done'])
         UserChoice = ['Rock','Paper','Scissors','Done'].index(UserChoice)
         ComputerChoice = computerchoice(ComputerChoice, Choices, UserChoice)
         if UserChoice == ComputerChoice:
                  ties = ties +1
                  rounds = rounds +1
                  CurrentStatus = "Tied"


         if UserChoice== 3:
                  x = 1
                  break

         elif UserChoice > ComputerChoice and UserChoice + ComputerChoice != 4:
                  wins = wins +1
                  rounds = rounds + 1
                  CurrentStatus = "Won"

         elif UserChoice < ComputerChoice and UserChoice + ComputerChoice != 4:
                  losses = losses +1
                  rounds = rounds +1
                  CurrentStatus = "Lost"

         elif UserChoice + ComputerChoice ==4 and UserChoice != ComputerChoice:
                  if Userchoice == 1:
                           score = score +1
                           rounds = rounds +1
                           CurrentStatus = "Won"
                  elif ComputerChoice == 1:
                          losses = losses +1
                          rounds = rounds +1

                          CurrentStatus = "Lost"


result = ["Cool.","Okay.","I am a failure"]
if wins>losses:
         easygui.msgbox("You won "+str(wins)+ " times, lost " +str(losses)+" times, tied "+ str(ties)+ " and won " +str(int(float(wins)/float(rounds)*100))+ "% of the time.","",result[0])
elif wins==losses:
         easygui.msgbox("You won "+str(wins)+ " times, lost " +str(losses)+" times, tied "+ str(ties)+ " and won " +str(int(float(wins)/float(rounds)*100))+ "% of the time.","",result[1])
elif wins<losses:
         easygui.msgbox("You won "+str(wins)+ " times, lost " +str(losses)+" times, tied "+ str(ties)+ " and won " +str(int(float(wins)/float(rounds)*100))+ "% of the time.","",result[2])

当我运行它时，它工作正常，但如果你按“摇滚”，那么你将永远平局/输球，永远不会赢。如果您按“剪刀”，那么您将永远平局/赢，永远不会输。我很确定这是同一个问题，但如果有人可以查看它，我将非常感激。

【问题讨论】：

标签： python easygui

【解决方案1】：

您确定获胜者的逻辑似乎有些复杂。或许可以尝试将其中的一些简化并提取到辅助函数中。

（此函数故意不必要地冗长）

def userWon(userChoice, computerChoice):
    if (userChoice == (computerChoice + 1 % 3)):
        return True
    if (computerChoice == (userChoice + 1 % 3)):
        return False
    if (computerChoice == userChoice):
        return None

请注意，您的剪刀石头布列表的顺序是，对于位置c 的任何给定选择，击败位置c + 1 mod 3 的选择。使用它，您可以使用这个辅助函数，如果用户赢了，则返回 True，如果输了，则返回 False，如果是平局，则返回 None。

然后你可以在调用它之前检查退出选项。

【讨论】：