CABasicAnimation 不适用于 UIImageView

Question

我有一个以编程方式调用的 UIImageView，我试图让它旋转但它不起作用。图像将放置在动态 UITableView 中（我无法将其更改为静态）。该图像在我的表格视图中看起来很好，但它只是不旋转。

- (void)viewDidLoad
{
    [super viewDidLoad];

    UIImageView *imageView = [[UIImageView alloc] initWithFrame:CGRectMake(20, 122, 38, 38)];
    imageView.image = [UIImage imageNamed:@"settings1.png"];

    [self.view addSubview:imageView];

    CABasicAnimation *spin;
    spin = [CABasicAnimation animationWithKeyPath:@"transform.rotation"];
    spin.fromValue = [NSNumber numberWithFloat:0];
    spin.toValue = [NSNumber numberWithFloat:((360*M_PI)/180)];
    spin.duration = 4;
    spin.repeatCount = 10*1000;

    [imageView.layer addAnimation:spin forKey:@"360"];

Answer 1

这可能是因为您试图在 viewDidLoad 中启动动画。我建议重新组织你的代码，在 viewDidLoad 中创建图像视图实例，然后等到 viewDidAppear: 被调用以实际启动动画。

@property (strong, nonatomic) UIImageView *imageView;

然后

- (void)viewDidLoad
{
    [super viewDidLoad];

    self.imageView = [[UIImageView alloc] initWithFrame:CGRectMake(20, 122, 38, 38)];
    self.imageView.image = [UIImage imageNamed:@"settings1.png"];

    [self.view addSubview:self.imageView];
}

- (void)viewDidAppear:(BOOL)animated
{
    [super viewDidAppear:animated];

    CABasicAnimation *spin = [CABasicAnimation animationWithKeyPath:@"transform.rotation"];
    spin.fromValue = [NSNumber numberWithFloat:0];
    spin.toValue = [NSNumber numberWithFloat:((360*M_PI)/180)];
    spin.duration = 4;
    spin.repeatCount = 10*1000;

    [self.imageView.layer addAnimation:spin forKey:@"360"];
}