将来自不同 foreach 循环的值组合成一个数组答案

【问题标题】：Combine values from different foreach loop into an array将来自不同 foreach 循环的值组合成一个数组
【发布时间】：2016-12-06 15:22:12
【问题描述】：

我正在尝试将两个 foreach() 循环值组合成一个数组并将其显示在一个表中。他们都有相同的字段，但我怎样才能在一个表中显示它而不是有两个不同的表？

<tr>
   <th> ID </th>
   <th> Transaction Type </th>
</tr>
<tbody>
   <?php 
      $ch = new CommissionHelper($rep);
      $data = $ch->getTransactionRecords($member);
        foreach ($data as $record ) {
      $d = ((object)$record);
      $pt = round($d->point, 2);
      ?>
   <tr>
      <td><?php echo $d->id;?></td>
      <td><?php echo $d->type;?></td>
   </tr>
   <?php
      }
      ?>
</tbody>
<tr>
   <th> ID </th>
   <th> Transaction Type </th>
</tr>
<tbody>
   <?php 
      $query = "SELECT * FROM invoice_withdraw_debit_card where user_ID like $id";
      $data = $MySQLi_CON->query($query);
      foreach ($data as $key ) {      
      ?>
   <tr>
      <td><?php echo $key['invoice_ID'];?></td>
      <td><?php echo $key['type'];?></td>
   </tr>
   <?php
      }
      ?>
</tbody>

【问题讨论】：

标签： php arrays

【解决方案1】：

你可以像下面这样实现它：-

<tr>
   <th> ID </th>
   <th> Transaction Type </th>
</tr>
<tbody>
   <?php 
      $ch = new CommissionHelper($rep);
      $data = $ch->getTransactionRecords($member);
        foreach ($data as $record ) {
      $d = ((object)$record);
      $pt = round($d->point, 2);
      ?>
   <tr>
      <td><?php echo $d->id;?></td>
      <td><?php echo $d->type;?></td>
   </tr>
   <?php
      }
      ?>
   <?php 
      $query = "SELECT * FROM invoice_withdraw_debit_card where user_ID like $id";
      $data = $MySQLi_CON->query($query);
      foreach ($data as $key ) {      
      ?>
   <tr>
      <td><?php echo $key['invoice_ID'];?></td>
      <td><?php echo $key['type'];?></td>
   </tr>
   <?php
      }
      ?>
</tbody>

注意：- 从代码中间删除 </tbody><tr><th> ID </th><th> Transaction Type </th></tr><tbody>

【讨论】：

fypforstack 很高兴为您提供帮助。干杯:):):)