mysql 在时间戳上按天查询组

Question

我有下表：

id   income created_at
-----------------------
966  300    1516182896
965  -1050  1516188513
964  2000   1516444061
963  600    1513267843

我正在运行以下查询以获取每天（过去 10 天）的收入总和：

SELECT sum(income) AS income, `created_at`
FROM `incomes`
WHERE `created_at` BETWEEN (UNIX_TIMESTAMP(NOW() - INTERVAL 10 DAY))
  AND UNIX_TIMESTAMP(NOW())
GROUP BY DATE(FROM_UNIXTIME("created_at"))

我刚刚得到：

income  created_at
-------------------
1850    1516182896

它给出了总和，而不管最后一次created_at的日期如何。

我错过了什么？

Answer 1

您正在转换字符串 created_at - 删除引号或使用 mysql 转义字符（反引号）。请注意，创建的 at 仍然不确定，您可能应该选择 DATE(FROM_UNIXTIME(created_at))

Answer 2

SELECT sum(income) AS income, DAYOFYEAR(FROM_UNIXTIME(created_at)) as doy
FROM `incomes`
WHERE `created_at` BETWEEN (UNIX_TIMESTAMP(NOW() - INTERVAL 10 DAY))
  AND UNIX_TIMESTAMP(NOW())
GROUP BY doy;

您按 varchar "created_at" 而不是列 created_at 分组时出错。

Answer 3

你应该添加日期来选择：

SELECT sum(income) AS income, `created_at`, DATE(FROM_UNIXTIME(`created_at`)) as dd
FROM `incomes`
WHERE `created_at` BETWEEN (UNIX_TIMESTAMP(NOW() - INTERVAL 10 DAY))
  AND UNIX_TIMESTAMP(NOW())
GROUP BY dd