Laravel API 控制器 |如何在控制器的这种“更新”方法中散列密码？

Question

这是我的 API 控制器中的方法，它假定更新用户数据。其中一列是密码，假设在插入之前进行哈希处理。

public function update($id, Request $request)
{
    $user = $this->userRepository->findWithoutFail($id);
    
    if (empty($user)) {
        return $this->sendResponse([
            'error' => true,
            'code' => 404,
        ], 'User not found');
    }
    $input = $request->except(['api_token']);
    try {
        if ($request->has('device_token')) {
            $user = $this->userRepository->update($request->only('device_token'), $id);
        } else {
            $customFields = $this->customFieldRepository->findByField('custom_field_model', $this->userRepository->model());
           
            $user = $this->userRepository->update($input, $id);
            
            foreach (getCustomFieldsValues($customFields, $request) as $value) {
            
                $user->customFieldsValues()
                    ->updateOrCreate(['custom_field_id' => $value['custom_field_id']], $value);
            }
        }
    } catch (ValidatorException $e) {
        return $this->sendError($e->getMessage(), 401);
    }

    return $this->sendResponse($user, __('lang.updated_successfully', ['operator' => __('lang.user')]));
}

现在，在使用此方法更新用户数据时，密码的原始文本被插入到用户表中。我希望使用以下代码对其进行哈希处理。但我不知道在上面的方法中应该去哪里。有人可以帮忙吗？？

 $user->password = Hash::make($request->input('password'));

将要更新的请求正文示例：

{"id":"147","name":"tipumon","email":"a@gmail.com","phone":"9898365627","useraddress":"test address","password":"passwordtext","api_token":"<apiTokenstring>","bio":"","media":{"id":null,"name":null,"url":"https://example.com/public/images/image_default.png","thumb":"https://example.com/public/images/image_default.png","icon":"https://example.com/public/images/image_default.png","formated_size":null}}

Answer 1

自己解决了。

   public function update($id, Request $request)
    {
         
        $user = $this->userRepository->findWithoutFail($id);
        
        if (empty($user)) {
            return $this->sendResponse([
                'error' => true,
                'code' => 404,
            ], 'User not found');
        }
        $input = $request->except(['api_token']);
        $input['password'] = Hash::make($request->input('password'));