为什么带有分页的spring nativeQuery会抛出SQLGrammarException？

【问题标题】：Why does spring nativeQuery with pagination throw a SQLGrammarException?为什么带有分页的spring nativeQuery会抛出SQLGrammarException？
【发布时间】：2017-04-10 07:26:18
【问题描述】：

我正在尝试在 Spring 4.2.4 中运行以下查询：

@Query(value="SELECT * FROM (SELECT ROW_NUMBER() OVER(ORDER BY i.TYPE_NUMBER ASC) AS RN, i.* FROM Item i) AS g WHERE RN between ?#{ #pageable.offset} and ?#{#pageable.offset + #pageable.pageSize}",
        countQuery="SELECT count(i.ID) FROM Item i",
    nativeQuery = true)
Page<Item> getItems(Pageable pageable);

此代码遵循此处显示的示例：https://github.com/spring-projects/spring-data-jpa/blob/master/src/test/java/org/springframework/data/jpa/repository/sample/UserRepository.java#L539

这会导致 SQLGrammarException：

Caused by: org.hibernate.exception.SQLGrammarException: could not extract ResultSet
    at org.hibernate.exception.internal.SQLStateConversionDelegate.convert(SQLStateConversionDelegate.java:123) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:126) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:112) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.extract(ResultSetReturnImpl.java:91) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.loader.Loader.getResultSet(Loader.java:2066) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1863) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1839) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.loader.Loader.doQuery(Loader.java:910) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:355) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.loader.Loader.doList(Loader.java:2554) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.loader.Loader.doList(Loader.java:2540) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2370) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.loader.Loader.list(Loader.java:2365) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.loader.custom.CustomLoader.list(CustomLoader.java:353) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.internal.SessionImpl.listCustomQuery(SessionImpl.java:1909) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.internal.AbstractSessionImpl.list(AbstractSessionImpl.java:311) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.internal.SQLQueryImpl.list(SQLQueryImpl.java:141) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.jpa.internal.QueryImpl.list(QueryImpl.java:573) ~[hibernate-entitymanager-4.3.11.Final.jar:4.3.11.Final]
    at org.hibernate.jpa.internal.QueryImpl.getResultList(QueryImpl.java:449) ~[hibernate-entitymanager-4.3.11.Final.jar:4.3.11.Final]
    at org.springframework.data.jpa.repository.query.JpaQueryExecution$PagedExecution.doExecute(JpaQueryExecution.java:191) ~[spring-data-jpa-1.9.4.RELEASE.jar:?]
    at org.springframework.data.jpa.repository.query.JpaQueryExecution.execute(JpaQueryExecution.java:78) ~[spring-data-jpa-1.9.4.RELEASE.jar:?]
    at org.springframework.data.jpa.repository.query.AbstractJpaQuery.doExecute(AbstractJpaQuery.java:100) ~[spring-data-jpa-1.9.4.RELEASE.jar:?]
    at org.springframework.data.jpa.repository.query.AbstractJpaQuery.execute(AbstractJpaQuery.java:91) ~[spring-data-jpa-1.9.4.RELEASE.jar:?]
    at org.springframework.data.repository.core.support.RepositoryFactorySupport$QueryExecutorMethodInterceptor.doInvoke(RepositoryFactorySupport.java:462) ~[spring-data-commons-1.11.4.RELEASE.jar:?]
    at org.springframework.data.repository.core.support.RepositoryFactorySupport$QueryExecutorMethodInterceptor.invoke(RepositoryFactorySupport.java:440) ~[spring-data-commons-1.11.4.RELEASE.jar:?]
    at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:179) ~[spring-aop-4.2.6.RELEASE.jar:4.2.6.RELEASE]
    at org.springframework.data.projection.DefaultMethodInvokingMethodInterceptor.invoke(DefaultMethodInvokingMethodInterceptor.java:61) ~[spring-data-commons-1.11.4.RELEASE.jar:?]
    at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:179) ~[spring-aop-4.2.6.RELEASE.jar:4.2.6.RELEASE]
    at org.springframework.transaction.interceptor.TransactionInterceptor$1.proceedWithInvocation(TransactionInterceptor.java:99) ~[spring-tx-4.2.6.RELEASE.jar:4.2.6.RELEASE]
    at org.springframework.transaction.interceptor.TransactionAspectSupport.invokeWithinTransaction(TransactionAspectSupport.java:281) ~[spring-tx-4.2.6.RELEASE.jar:4.2.6.RELEASE]
    at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:96) ~[spring-tx-4.2.6.RELEASE.jar:4.2.6.RELEASE]
    at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:179) ~[spring-aop-4.2.6.RELEASE.jar:4.2.6.RELEASE]
    at org.springframework.dao.support.PersistenceExceptionTranslationInterceptor.invoke(PersistenceExceptionTranslationInterceptor.java:136) ~[spring-tx-4.2.6.RELEASE.jar:4.2.6.RELEASE]

这是caused，作者：

com.microsoft.sqlserver.jdbc.SQLServerException: Incorrect syntax near ','.
    at com.microsoft.sqlserver.jdbc.SQLServerException.makeFromDatabaseError(SQLServerException.java:216) ~[sqljdbc4.jar:?]
    at com.microsoft.sqlserver.jdbc.SQLServerStatement.getNextResult(SQLServerStatement.java:1515) ~[sqljdbc4.jar:?]...

我尝试在没有分页的情况下运行相同的本机查询，它会运行而不会出现任何错误。查询如下所示：

  @Query(value="SELECT * FROM (SELECT ROW_NUMBER() OVER(ORDER BY i.TYPE_NUMBER ASC) AS RN, i.* FROM Item i) AS g WHERE RN between 0 and 50",
        nativeQuery = true)
    List<Item> getItems();

这是弹簧数据的限制还是我在这里遗漏了什么？

【问题讨论】：

  • 那个SQLGrammarException 有cause 吗？
  • 是的，原因如下：Caused by: com.microsoft.sqlserver.jdbc.SQLServerException: Incorrect syntax near ','. 只有在使用 Pageable 对象运行时才会发生这种情况。
  • 开启sql日志查看执行的sqlstackoverflow.com/documentation/hibernate/3548/…
  • @DanielKäfer 谢谢。我在hibernate上启用了SQL调试，发现问题出在Pageable对象的动态排序上：PageRequest pageRequest = new PageRequest(0, 25, Sort.Direction.ASC, "itemCategory");使用pageable对象上的动态排序参数Hibernate生成SELECT top 25 * FROM (SELECT ROW_NUMBER() OVER(ORDER BY i.TYPE_NUMBER ASC) AS RN, i.* FROM Item i) AS g WHERE RN between ? and ?, i.itemCategory asc这里的错误非常明显。你知道在原生查询中使用 pageable 的排序参数的方法吗？

标签： java spring hibernate spring-data nativequery


【解决方案1】：

我认为这是 spring 数据中的一个错误。如果查询包含 ORDER BY，则 Spring 数据附加 , i.itemCategory asc。在另一种情况下，spring 数据添加ORDER BY i.itemCategory asc。作为解决方法，您可以将 ORDER BY 1=1 添加到查询中。

@Query(value="SELECT * FROM (SELECT ROW_NUMBER() OVER(ORDER BY i.TYPE_NUMBER ASC) AS RN, i.* FROM Item i) AS g WHERE RN between ?#{ #pageable.offset} and ?#{#pageable.offset + #pageable.pageSize}, ORDER BY 1=1",
        countQuery="SELECT count(i.ID) FROM Item i",
    nativeQuery = true)
Page<Item> getItems(Pageable pageable);

【讨论】：

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