基于列唯一值创建新数据框

Question

我有一个如下的df：-

StartTime	Location	Sales
2021-09-22 00:00:00	New York	10
2021-09-22 00:00:00	Delhi	20
2021-09-22 00:05:00	New York	10
2021-09-22 00:05:00	Delhi	20
2021-09-23 00:00:00	New York	10
2021-09-23 00:00:00	Delhi	20
2021-09-23 00:05:00	New York	10
2021-09-23 00:05:00	Delhi	20

我已将日期从“开始时间”列中分离出来

    df['dateSeparate'] = df['StartTime'].str.extract('(\d\d\d\d-\d\d-\d\d)', expand=False).str.strip()
print(df)

新的df看起来像

StartTime	Location	Sales	dateSeparate
2021-09-22 00:00:00	New York	10	2021-09-22
2021-09-22 00:00:00	Delhi	20	2021-09-22
2021-09-22 00:05:00	New York	10	2021-09-22
2021-09-22 00:05:00	Delhi	20	2021-09-22
2021-09-23 00:00:00	New York	10	2021-09-23
2021-09-23 00:00:00	Delhi	20	2021-09-23
2021-09-23 00:05:00	New York	10	2021-09-23
2021-09-23 00:05:00	Delhi	20	2021-09-23

我可以知道有什么方法可以根据“dateSeparate”中的不同日期创建新的数据框吗？

提前谢谢你。

Answer 1

试试这个：

df['StartTime'] = pd.to_datetime(df.StartTime) # if value in StartTime is string use this line.

df['dateSeparate'] = df['StartTime'].dt.strftime('%y-%m-%d')