如何检查对象属性是否也存在于另一个对象中？答案

【问题标题】：How to check if an objects property exists in another one too?如何检查对象属性是否也存在于另一个对象中？
【发布时间】：2019-06-22 00:43:44
【问题描述】：

我有两个不同的对象，如果第二个对象的至少一个属性与第一个匹配，我想返回 true。如果不是，则返回 false。我尝试过 .hasOwnProperty 和 .keys 方法，但无法处理。下面是一个示例代码。谢谢。

let propchecker = (a,b) =>{
    if(/* at least one property matches exact */){
        return true;
     }

    else {
        return false;
    }
}

let origin = {name: "John", surname: "Doe"};

let first = {name: "John", surname: "Roe" };
let second = {name: "Jane", surname: "Doe"};
let third = {name: "Richard", surname: "Roe"};

console.log(propchecker(origin,first)); //Should return True.
console.log(propchecker(origin,second)); //Should return True.
console.log(propchecker(origin,third)); //Should return False.

【问题讨论】：

应该尽可能通用还是检查姓名和姓氏就足够了？
泛型应该更好

标签： javascript

【解决方案1】：

可能有更短的解决方案，但这很好用

let propchecker = (a,b) =>{
for (let key in a) {
  for (let key2 in b ){
    if(a[key] == b[key2]){
     return true
   }
 }
}
return false
}

let origin = {name: "John", surname: "Doe"};

let first = {name: "John", surname: "Roe" };
let second = {name: "Jane", surname: "Doe"};
let third = {name: "Richard", surname: "Roe"};

console.log(propchecker(origin,first)); //Should return True.
console.log(propchecker(origin,second)); //Should return True.
console.log(propchecker(origin,third)); //

【讨论】：

【解决方案2】：

您可以使用Object.keys() 获取一个对象的键，然后在其上使用some()。

let propchecker = (a,b) => Object.keys(a).some(x => a[x] === b[x])

let origin = {name: "John", surname: "Doe"};

let first = {name: "John", surname: "Roe" };
let second = {name: "Jane", surname: "Doe"};
let third = {name: "Richard", surname: "Roe"};

console.log(propchecker(origin,first)); //Should return True.
console.log(propchecker(origin,second)); //Should return True.
console.log(propchecker(origin,third)); //Should return False.

【讨论】：

这是较短的解决方案，不错
@SirDad 如果认为最适合您，请考虑接受他的回答。
是的，当然，兄弟，它应该是最好的答案，谢谢

【解决方案3】：

试试这个

let propchecker = (a,b) =>{
   result =  false;
   for(let ele in first){
       result  = result  || (a[ele] === b[ele])
    }
   return result
 }

let origin = {name: "John", surname: "Doe"};

let first = {name: "John", surname: "Roe" };
let second = {name: "Jane", surname: "Doe"};
let third = {name: "Richard", surname: "Roe"};

console.log(propchecker(origin,first)); //Should return True.
console.log(propchecker(origin,second)); //Should return True.
console.log(propchecker(origin,third)); //Should return False.

【讨论】：

【解决方案4】：

看起来它已经被回答了，但我也会把我的帽子扔进擂台上。所有这些答案都在做几乎相同的事情。

let propchecker = (a,b) =>{
    var check = false;
    Object.keys(a).forEach(function(key) {
        if(a[key] == b[key]) {
            check = true;
        }
    })

    return check;
}

let origin = {name: "John", surname: "Doe"};

let first = {name: "John", surname: "Roe" };
let second = {name: "Jane", surname: "Doe"};
let third = {name: "Richard", surname: "Roe"};

console.log(propchecker(origin,first)); //Should return True.
console.log(propchecker(origin,second)); //Should return True.
console.log(propchecker(origin,third)); //Should return False.

【讨论】：