Laravel 从选定的多行批量插入到另一个表

Question

我希望我可以将多行从特定表复制到另一个表。但问题是，它无法复制密码字段数据和 spatie assignRole()。然而，电子邮件、姓名、用户名等所有字段都可以正常工作。

public function approveMultiple(Request $request) {
        $get_ids = $request->ids;
        $ids = explode(',', $get_ids);

        $users = \App\Applicant::whereIn('id', $ids);
        $users->update(['status' => 'Approved']); 

        $find_selected = \App\Applicant::whereIn('id', $ids)->get();
        $find_selected->makeHidden(['status', 'id']);
        $find_selected->makeVisible(['password']);
        $new_users = $find_selected->toArray();
        $users = \App\User::insert($new_users);

        //problem still lays here
        //$users->assignRole('Applicant');
        //$users->save();

        return response()->json(['success' => "Selected User(s) successfully approved."]);
    }

尝试这种方法但只插入一条记录

public function approveMultiple(Request $request) {
        $get_ids = $request->ids;
        $ids = explode(',', $get_ids);

        //$users = \App\Applicant::whereIn('id', $ids);
        //$users->update(['status' => 'Approved']); 

        //$find_selected = \App\Applicant::whereIn('id', $ids)->get();
        $find_selected = \App\Applicant::whereIn('id', $ids)->firstOrFail();
        $find_selected->makeHidden(['status', 'id']);
        $find_selected->makeVisible(['password']);
        $new_users = $find_selected->toArray();
        //$users = \App\User::insert($new_users);


        $users = \App\User::create([
            'name' => $find_selected->name,
            'username' => $find_selected->username,
            'gender' => $find_selected->gender,
            'email' => $find_selected->email,
            'phone' => $find_selected->phone,
            'password' => $find_selected->password,
            'created_at' => $find_selected->created_at,
            'updated_at' => $find_selected->updated_at,
        ]);

        //problem lays here
        $users->assignRole('Applicant');
        $users->save();

        return response()->json(['success' => "Selected User(s) successfully approved."]);
    }

Answer 1

关于密码字段，您需要使用如下功能使其可见：makeVisible

例如：

$users->makeVisible('password')->toArray();

编辑 1：

关于assignRole你必须在调用save()方法后分配角色

例如：

$users->password = $find_selected->password;
$users->save();
$users->assignRole('Applicant');

编辑 2：

public function approveMultiple(Request $request) {
        $get_ids = $request->ids;
        $ids = explode(',', $get_ids);

        //$users = \App\Applicant::whereIn('id', $ids);
        //$users->update(['status' => 'Approved']); 

        $find_selected = \App\Applicant::whereIn('id', $ids)->get();
        //$find_selected = \App\Applicant::whereIn('id', $ids)->firstOrFail();
        $find_selected->makeHidden(['status', 'id']);
        $find_selected->makeVisible(['password']);
        $new_users = $find_selected->toArray();
        //$users = \App\User::insert($new_users);

        foreach($find_selected as $new_users){
           $user = \App\User::create($new_users);
           $user->assignRole('Applicant');
        }

        return response()->json(['success' => "Selected User(s) successfully approved."]);
    }

Answer 2

我认为问题出在这一行：

$users = \App\User::insert($new_users);

insert 方法返回一个布尔值，指示插入操作是否成功... 所以你 $users 变量将持有一个布尔值...... 和

$users->assignRole('Applicant');
 $users->password = $find_selected->password;

不会工作

你可以使用：

$find_selected->makeVisible(['password']);

foreach($find_selected as $user)
{
$newUser= new User();
$newUser->password = $user->password;
$newUser->save();
$newUser->assignRole('Applicant');
}