Python的骰子滚轮答案

【问题标题】：Dice Roller for PythonPython的骰子滚轮
【发布时间】：2018-01-09 15:25:24
【问题描述】：

我正在尝试在 python 中制作一个掷骰子的程序，该程序根据用户在边、骰子和掷骰上的输入来掷骰子。目前这段代码或多或少有效，但我遇到的问题是说我给3 掷骰子3 次6 边。

我的代码显示为输出：

Roll #1 6
Roll #2 5
Roll #3 1
Roll #4 6
Roll #5 4
Roll #6 6
Roll #7 3
Roll #8 1
Roll #9 1

当我需要它显示为：

Roll #1 6 5 1
Roll #2 6 4 6
Roll #3 3 1 1

到目前为止，这是我的代码。我的猜测是它必须与我的参数和参数为空有关？我不完全确定。这是我的代码：

import random

def main ():
    rolls = get_rolls()
    dice = get_dice()
    sides = get_sides()

    nrolls = 1
    for r in range (rolls):
        for d in range (dice):
            print ('Roll #', nrolls, random.randint(1,sides))
            nrolls += 1 

def get_rolls():
    rolls = int(input('Enter the number of rolls: '))
    while rolls <= 0:
        print ('Number of rolls must be higher than 0')
        rolls = int (input('Enter the number of rolls: '))
    return rolls

def get_dice():
    dice = int (input('Enter the number of dice being rolled: '))
    while dice < 1 or 5 < dice:
        print ('Number of dice being rolled must be between 1 and 5')
        dice = int (input('Enter the number of dice being rolled: '))
    return dice ()

def get_sides():
    sides = int (input('Enter the number of sides on the dice: '))
    while sides < 2 or 36 < sides:
        print ('Number of sides on dice must be between 2 and 36')
        sides = int (input('Enter the number of sides on the dice: '))
    return sides


main()

【问题讨论】：

标签： python nested-loops dice

【解决方案1】：

您的问题是您将print 语句放在内部for 循环中，这意味着您打印结果的次数过多，并且增加nrolls 的次数也过于频繁。

nrolls = 1
for r in range (rolls):
    roll = []
    for d in range (dice):
        roll.append(random.randint(1,sides))
    print('Roll #', nrolls, *roll)
    nrolls += 1
>Roll # 1 3 3 1
>Roll # 2 1 5 2
>Roll # 3 6 5 4

【讨论】：

【解决方案2】：

为了对您的代码进行最少的修改，请将其更改为：

for r in range (rolls):
    print('Roll #', nrolls, end=' ')
    for d in range (dice):
        print (random.randint(1,sides), end=' ')
    print()
    nrolls += 1

此外，以下行会引发错误。

return dice ()

改成：

return dice

【讨论】：

【解决方案3】：

import random

def dice_roll(n):
dicelist = ['\u2680','\u2681','\u2682','\u2683','\u2684','\u2685']
dicevalue = {(dicelist[0]): 1, (dicelist[1]): 2, (dicelist[2]): 3, 
(dicelist[3]): 4, (dicelist[4]): 5,(dicelist[5]): 6}
result = 0
visualresult = " "

for i in range(n): 
    random_roll = random.sample((dicelist), 1)
    str1 = str(random_roll)
    str2 = str1.replace("'"," ")
    str3 = str2.replace("[", " ")
    str4 = str3.replace(']',' ')
    str5 = str4.strip()
    valueresultindex = dicelist.index(str5)
    valuelist = list(dicevalue.values())
    newvalueindex = valuelist[valueresultindex]
    result = result + newvalueindex
    visualresult = visualresult + str4
    i = i + 1

rolledstring = "You rolled this much: "    
print(visualresult)
print((rolledstring) + str(result))

Numofdice = int(input("Please enter the amount of dice you would like to 
roll: "))

if Numofdice >= 1 and Numofdice <= 6:
    ValidRollAmount = True
else:
    ValidRollAmount = False

while ValidRollAmount == False:
    Numofdice = int(input("Invalid amount of dice please re-enter: "))    
    if Numofdice >= 1 and Numofdice <= 6:
        ValidRollAmount = True

while ValidRollAmount == True:
    dice_roll(Numofdice)
    ValidRollAmount = False

【讨论】：

【解决方案4】：

您应该使用 while 循环来继续要求骰子，然后滚动该数量的骰子。

例如

import random
from random import randint
import string

while True:
  str = input("What dice would you like to roll")
  prefix, d, suffix = str.partition("d")
  if str == "quit" or str == "q":
    break
  elif str.startswith("d"):
    print random.randint(1, int(suffix))
  elif str.startswith(prefix):
    for _ in range(int(prefix)):
      print (random.randint(1, int(suffix)))
  elif str.startswith("d"):
    print random.randint(1, suffix)
  else:
   print ("Keep rolling or type q or quit")

print ("exiting")

【讨论】：