如何在 Linux 托管的 NodeJS 上打开 .exe 文件

Question

我正在尝试让我的节点服务器在 Linux 托管的 NODEJS 实现上启动一个 .exe 文件

我的 .exe 位于此处：'/home/username/projects/ProjectName/server/webserver/Project.exe'

当我尝试启动 exe 时

与：

   exec('/home/username/projects/ProjectName/server/webserver/Project.exe', ["/home/username/projects/ProjectName/server/webserver/files/"+date], function(err, data) {
}

我收到文件不喜欢的错误

看起来像这样：

{ Error: Command failed: /home/username/projects/ProjectName/server/webserver/Project.exe /home/username/projects/ProjectName/server/webserver/files/31005
/home/username/projects/ProjectName/server/webserver/Project.exe: 1: /home/username/projects/ProjectName/server/webserver/Project.exe: MZ�##���@�#��: not found
/home/username/projects/ProjectName/server/webserver/Project.exe: 2: /home/username/projects/ProjectName/server/webserver/Project.exe: Syntax error: ")" unexpected

    at ChildProcess.exithandler (child_process.js:294:12)
    at ChildProcess.emit (events.js:198:13)
    at maybeClose (internal/child_process.js:982:16)
    at Socket.stream.socket.on (internal/child_process.js:389:11)
    at Socket.emit (events.js:198:13)
    at Pipe._handle.close (net.js:606:12)
  killed: false,
  code: 2,
  signal: null,
  cmd:
   '/home/username/projects/ProjectName/server/webserver/Project.exe /home/username/projects/ProjectName/server/webserver/files/31005' }

当尝试在基于 Windows 的 NodeJS 上使用 Windows 目录而不是 linux 运行相同的功能时，它可以在 Linux 上通过 Wine 打开文件，我的函数调用中是否有某个地方我需要引导它打开.exe 与 WINE？如果是这样，我该怎么做？

Answer 1

试试这个

const { exec} = require('child_process');
 exec('wine /home/username/projects/ProjectName/server/webserver/Project.exe /home/username/projects/ProjectName/server/webserver/files/'+date,
function(err, data){

});

https://superuser.com/questions/1058985/launch-program-with-wine-using-exe-arguments https://stackoverflow.com/a/49069169/12167785

Answer 2

我通过以下方式获得了我想要的功能：

exec("wine", ["/home/username/projects/ProjectName/server/webserver/Project.exe", date], function(err,data){
}