如何在 python discord.py Discord Bot 中使用用户输入

Question

Discord.py 摇滚、剪纸、剪纸游戏的用户输入。

我想创建一个Discord Bot，它可以玩石头、剪纸、玩剪刀。我认为游戏的基本代码并不复杂，但discord.py 的实现对我来说很难。 问题可能是这行代码player = await bot.wait_for('message')。我已阅读 discord.py 文档，但它似乎无法正常工作。 这是我的代码：

@bot.command(pass_context=True, aliases=['g', 'ga', 'gam'])
@commands.guild_only()
async def game(ctx):
    await ctx.send(
        'Hallo, wie gehts denn so ' + ctx.message.author.mention + '? Lust auf eine Runde Schere, Stein, Papier?')

    wins = 0
    losses = 0
    ties = 0

    while True:
        await ctx.send('%s Siege, %s Niederlagen, %s Unentschieden \n' % (wins, losses, ties))
        while True:
            await ctx.send('Auf was setzt du? (s)tein, (p)apier, (sc)here oder (q)uit')  
            player = await bot.wait_for('message') 
            print(str(player))
            if player == 'q':
                return
            if player == 's' or player == 'p' or player == 'sc':
                break
            await ctx.send('Schreib s, p, sc oder q!')

        if player == 's':
            await ctx.send('Stein gegen...')
        elif player == 'p':
            await ctx.send('Papier gegen...')
        elif player == 'sc':
            await ctx.send('Schere gegen...')

        randomnum = random.randint(1, 3)
        if randomnum == 1:
            computer = 's'
            await ctx.send('Stein!')
        elif randomnum == 2:
            computer = 'p'
            await ctx.send('Papier!')
        elif randomnum == 3:
            computer = 'sc'
            await ctx.send('Schere!')

        if player == computer:
            await ctx.send('Unentschieden!')
            ties = ties + 1
        elif player == 's' and computer == 'sc':
            await ctx.send('Du gewinnst!')
            wins = wins + 1
        elif player == 's' and computer == 'p':
            await ctx.send('Ich habe gewonnen!')
            losses = losses + 1
        elif player == 'p' and computer == 's':
            await ctx.send('Du gewinnst!')
            wins = wins + 1
        elif player == 'p' and computer == 'sc':
            losses = losses + 1
            await ctx.send('Ich habe gewonnen!')
        elif player == 'sc' and computer == 'p':
            await ctx.send('Du gewinnst!')
            wins = wins + 1
        elif player == 'sc' and computer == 's':
            await ctx.send('Ich habe gewonnen!')
            losses = losses + 1

Answer 1

您可能想写一张支票，以便它知道作者是谁。

def check(author):
    def inner_check(message):
        return message.author == author
    return inner_check

然后您将通过使用适当的参数调用 outer_check 将 inner_check 传递给 wait_for：

playerChoice = await bot.wait_for('message', check=check(context.author), timeout=30)

Answer 2

我找到了解决方案。只需将 player 变量更改为 player.content 即可。

if player.content == 

感谢您的努力！