有没有一种方法可以暂停一个函数但不影响 Python 中的其他函数？

Question

所以基本上我是在 python 中编写一个不和谐的机器人。它是一个机器人，您可以在其中从商店购买/出售东西，并外出耕种或采矿以获取资源。我需要帮助的主要一点是让函数休息大约 5 分钟。这个机器人可能会在 5 分钟内被多次使用，所以我不能暂停整个代码。显然 time.sleep 将不起作用，因为它会暂停整个脚本。我尝试了一些不同的方法，但效果不佳，我在互联网上找不到太多其他东西。我的代码是：

    @client.command()
async def farm(ctx, item):
    fakelocation = 11
    await get_bank_data()
    users = await get_bank_data()
    if users[str(ctx.author.id)]["location"] == "Farm":
        item = item.lower()
        returnholder = 6
        product = "none"
        user = ctx.author
        users = await get_bank_data()
        if item == "potato":
            product = "potato"
            amount = random.randrange(2, 10)
            await ctx.send("Your crops will be given to you at the end of the session!")
            returnholder = 5
        if item == "carrot":
            product = "carrot"
            amount = random.randrange(4, 12)
            await ctx.send("Your crops will be given to you at the end of the session!")
            returnholder = 5
        if item == "wheat":
            product = "wheat"
            amount = random.randrange(7, 15)
            await ctx.send("Your crops will be given to you at the end of the session!")
            returnholder = 5
        if item == "apple":
            product = "apple"
            amount = random.randrange(2, 13)
            await ctx.send("Your crops will be given to you at the end of the session!")
            returnholder = 5
        if item == "banana":
            product = "banana"
            amount = random.randrange(4, 10)
            await ctx.send("Your crops will be given to you at the end of the session!")
            returnholder = 5
        if item == "orange":
            product = "orange"
            amount = random.randrange(3, 8)
            await ctx.send("Your crops will be given to you at the end of the session!")
            returnholder = 5
        if returnholder == 6:
            await ctx.send("That crop does not exist here!")
            return
        try:
            index = 0
            t = None
            for thing in users[str(user.id)]["bag"]:
                n = thing["item"]
                if n == item:
                    old_amt = thing["amount"]
                    new_amt = old_amt + amount
                    users[str(user.id)]["bag"][index]["amount"] = new_amt
                    t = 1
                    break
                index += 1
            if t == None:
                obj = {"item": product, "amount": amount}
                users[str(user.id)]["bag"].append(obj)
        except:
            obj = {"item": product, "amount": amount}
            users[str(user.id)]["bag"] = [obj]
        with open("mainbank.json", "w") as f:
            json.dump(users, f)
        fakelocation = 4
    if fakelocation == 11:
        await ctx.send("Please move to the Farm to farm!")
        return

这是代码，和Mine函数比较相似。它会检查项目是什么，然后如果它存在，它会给你随机数量的项目。我想让它在try: 中停止第一件事，否则它会在时间到之前给你项目。感谢您的帮助！

Answer 1

import asyncio

await asyncio.sleep(SECONDS)

这就是我的答案。感谢@TinNguyen 简单地回答了我的问题。