如何实现列表答案

【问题标题】：how to implement a list如何实现列表
【发布时间】：2013-11-27 03:02:21
【问题描述】：

我正在尝试创建井字游戏；但我有一点麻烦。 I have created a list with numbers in it, so when that number is chosen it changes to an x or o.但是，当我的电路板打印时，其中包含数字 0,1,2,3,4,5,6,7,8，我不希望它们那样。我的问题是如何更改空列表中的字符？我会使用索引还是有其他方法呢

board = [0,1,2,
         3,4,5,
         6,7,8]

def gameBoard():
    print("    " "a" "   " "b" "   " "c")
    print("  ""-------------")
    print(("1"),("|"),board[0],"|",board[1], "|" ,board[2], "|")
    print("  ""-------------")
    print(("2"),("|"),board[3],"|",board[4], "|" ,board[5], "|")
    print("  ""-------------")   
    print(("3"),("|"),board[6],"|",board[7], "|" ,board[8], "|")
    print("  ""-------------")    


while True:
    user_input = input("Enter your move: ")
    if user_input == "a1":
        user_input = "0"
    elif user_input == "a2":
        user_input = "3" 
    elif user_input == "a3":
        user_input="6"
    elif user_input == "b1":
        user_input = "1"
    elif user_input == "b2":
        user_input = "4"
    elif user_input== "b3":
        user_input = "7"
    elif user_input == "c1":
        user_input = "2"
    elif user_input == "c2":
        user_input = "5"
    elif user_input == "c3":
        user_input = "8"
    else:
        print("invalid coordinates")
    user_input= int(user_input)

【问题讨论】：

标签： python list python-3.x tic-tac-toe

【解决方案1】：

我猜你想要的是一个带有字符串而不是数字的板，最初用单个空格的字符串填充。您可以为此板使用单个列表或二维数组

单列表实现

board = [" "," "," "," "," "," "," "," "," "]

控制台示例：

>>> board = [" "," "," "," "," "," "," "," "," "]
>>> board[2] = "X"
>>> board
[' ', ' ', 'X', ' ', ' ', ' ', ' ', ' ', ' ']
>>> board[0]
' '
>>> board[2]
'X'
>>>

二维数组实现

board = [[" "," "," "],[" "," "," "],[" "," "," "]]

控制台示例：

>>> board = [[" "," "," "],[" "," "," "],[" "," "," "]]
>>> board[1][2] = "O"
>>> board
[[' ', ' ', ' '], [' ', ' ', 'O'], [' ', ' ', ' ']]
>>> board[0][1]
' '
>>> board[1][2]
'O'

打印二维列表示例：

>>> board = [["X"," ","X"],[" ","X"," "],["X"," ","X"]]
>>> for row in board:
    string = ""
    for element in row:
        string = string + element
    print(string)


X X
 X 
X X

【讨论】：

这就是我想要的方式。但它也假设在实际的井字游戏板上打印出来。我怎么做？因为它们是这样的，它以直线打印出来

【解决方案2】：

从您的代码中，您正在用整数 0 - 8 填充板。如果您检查板 [7]，它将返回 7。

我认为您想用空格初始化板，以便板 [7] 将返回 ' '（空格）。

你可以做 board = [' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ']

或者更干净，

板 = [''] * 9

希望这会有所帮助:) 使用矩阵也不是一个坏主意，但与您尝试解决的问题不同

【讨论】：

【解决方案3】：

使用二维列表！

board = [[0,0,0],
         [0,0,0],
         [0,0,0]]

然后只需使用您想要的值等。然后参考就是：

board[row][column]

编辑：我有点误读了这个问题，而不是 0 到 9，您可以将它们全部设为空字符串，即

board[i] = ''

或使用字典将数字映射到字符串

board[5] = ''

【讨论】：

【解决方案4】：

您可以使用字典：

board = {0:'X', 1:'O', 2:' ',
         3:'X', 4:'O', 5:' ',
         6:'X', 7:'O', 8:' ',
        }

print board[1] # will print O
board[1] = 'X'
print board[1] # will print X

【讨论】：

【解决方案5】：

您的问题并不完整，因为您没有在每次迭代时更新游戏板。不过，这里有一些建议：

将您的初始板设置为全零（或“O”）
如果您使用的是列表，您的所有语句（如 user_input = '1' 等）都可以简单地设置为 use_input = 1，以避免显式调用 int。
您只需说出board[user_input] = 'X' 或board[user_input] = 'O' 即可更改列表的值，具体取决于播放器。

【讨论】：