【发布时间】:2016-03-10 07:38:00
【问题描述】:
我正在努力获得在 Firebase 查询后解决的承诺。本质上,我想从一个表中获取所有指定的键,然后遍历另一个表以获得我想要的艺术品。
artistFactory.js
'use strict';
angular.module('artvoicesApp')
.factory('Artist', function(localStorageService, FIREBASE_URL, $q) {
var artistData = {};
var userKey = localStorageService.get('userKey');
var accountKey = localStorageService.get('accountKey');
var artistRef = FIREBASE_URL.child('v2/artist');
var accountRef = FIREBASE_URL.child('v2/account/' + accountKey);
var userRef = FIREBASE_URL.child('v2/user/' + userKey);
artistData.addArtist = function(artistName) {
var artist = artistRef.push();
accountRef.child('artists/' + artist.key()).set(true);
userRef.child('artists/' + artist.key()).set(true);
artist.set({name: artistName});
artist.child('users/' + userKey).set(true);
artist.child('accounts/' + accountKey).set(true);
};
artistData.getArtistKeys = function() {
var artistKeys = [];
var defer = $q.defer();
accountRef.child('artists').once('value', function(snapshot) {
snapshot.forEach(function(childSnapShot) {
artistKeys.push(childSnapShot.key());
});
defer.resolve(artistKeys);
});
return defer.promise;
};
artistData.getArtists = function(artistKeys) {
var artistObj = {};
var artistRef = FIREBASE_URL.child('v2/artist');
var defer = $q.defer();
artistKeys.forEach(function(artist) {
artistRef.child(artist).once('value', function(snapshot) {
artistObj[artist] = snapshot.val();
});
defer.resolve(artistObj);
});
return defer.promise;
};
return artistData;
});
artwork.controller.js
Artist.getArtistKeys().then(function(artistKeys) {
Artist.getArtists(artistKeys).then(function(artists) {
vm.artists = artists;
console.log(vm.artists);
});
});
如果我将 vm.artwork 设置为超时,它会返回相应的数据。
【问题讨论】:
标签: javascript angularjs q angular-promise