计算数据框中的特定关键字答案

【问题标题】：Counting specific keywords in a dataframe计算数据框中的特定关键字
【发布时间】：2019-12-25 13:26:19
【问题描述】：

我有一个这样的数据框：

    A
0   Please wait outside of the house
1   A glittering gem is not enough.
2   The memory we used to share is no longer coher...
3   She only paints with bold colors; she does not...

我有一组关键字：

keywords = ["of","is","she"]

如何为每个关键字创建一个列，其中包含该关键字在我的数据框的每个句子中出现的次数？它看起来像：

                                                   A  of  is  she
0                   Please wait outside of the house   1   0    0
1                    A glittering gem is not enough.   0   1    0
2  The memory we used to share is no longer coher...   0   1    0
3  She only paints with bold colors; she does not...   0   0    2

注意：我查看了how to count specific words from a pandas Series?，但它没有回答我的问题。

【问题讨论】：

标签： python pandas

【解决方案1】：

我假设您正在寻找不区分大小写的匹配项。

import pandas as pd
df = pd.DataFrame({
    'A': [
        'Please wait outside of the house',
        'A glittering gem is not enough.',
        'The memory we used to share is no longer coher...',
        'She only paints with bold colors; she does not...'
    ]
})
keywords = ["of","is","she"]
for keyword in keywords:
    df[keyword] = df['A'].apply(lambda _str: _str.lower().count(keyword))
print(df)

输出

                                                   A  of  is  she
0                   Please wait outside of the house   1   0    0
1                    A glittering gem is not enough.   0   1    0
2  The memory we used to share is no longer coher...   0   1    0
3  She only paints with bold colors; she does not...   0   0    2

【讨论】：

【解决方案2】：

你也可以这样做：

df['is'] = df.A.str.count(r'is', flags=re.IGNORECASE)
df['of'] = df.A.str.count(r'of', flags=re.IGNORECASE)
df['she'] = df.A.str.count(r'she', flags=re.IGNORECASE)


                                                   A  of  is  she
0                   Please wait outside of the house   1   0    0
1                    A glittering gem is not enough.   0   1    0
2  The memory we used to share is no longer coher...   0   1    0
3  She only paints with bold colors; she does not...   0   0    2

【讨论】：