IndexError: list index out of range if words[i+1] in vector: for c in range(len(vector)):答案

【问题标题】：IndexError: list index out of range if words[i+1] in vector: for c in range(len(vector)):IndexError: list index out of range if words[i+1] in vector: for c in range(len(vector)):
【发布时间】：2021-06-10 14:50:33
【问题描述】：

我编写了一些 python 代码来使用词频列表对来自文本语料库的数据进行矢量化。我的这行代码出现 IndexError: list index out of range 错误；

if words[i+1] in vector:
                for c in range(len(vector)):

我正在创建一个从词频列表向量化数据语料库的代码，完整代码如下：

# Process the original data, use a sliding window, convert the original data into vector form, and generate training samples.

def loadData():
    # Processing raw data
    data1 = open(r"ChinaCorpus.txt", 'r').read()
    data1 = data1.replace('[', '')
    data1 = data1.replace(']', '')
    words = data1.split()
    i = 0
    while i < len(words):           # Remove the previous date factor and reduce its impact on parameter adjustment
        if "1998" in words[i]:
            del words[i]
            i = i - 1
        i += 1
    lables = []
    print(len(words))
    for i in range(len(words)):
        t = words[i].find('/')
        lables.append(words[i][t:])
        words[i] = words[i][0:t]
    data2 = open(r"WordFreq.txt", "r",encoding= 'UTF-8').read()
    vector = data2.split()
    with open("VectorData.txt", "a", encoding='utf-8') as f:
        for i in range(1,len(words)):
            flag = 0
            s = ""
            if words[i-1] in vector:
                for a in range(len(vector)):
                    if words[i-1] == vector[a]:
                        s += str(a)
                        s += ' '
                        break
            else:
                s += '0 '
            if words[i] in vector:
                for b in range(len(vector)):
                    if words[i] == vector[b]:
                        s += str(b)
                        s += ' '
                        if lables[i] == "/ns":
                            flag = 1
                        break
            else:
                s += '0 '
            if words[i+1] in vector:
                for c in range(len(vector)):
                    if words[i+1] == vector[c]:
                        s += str(c)
                        s += ' '
                        break
            else:
                s += '0 '
            if flag == 1:
                s += '1'
            else:
                s += '0'
            s += '\n'
            print(i)
            f.write(s)
    f.close()

if __name__ == '__main__':
    loadData()

错误截图：

Error

【问题讨论】：

words[i+1] 在出现words[len(words) + 1] 时会报错。尝试改用range(1, len(words) -1)
就是这样，谢谢！

标签： python

【解决方案1】：

如果向量包含 3 个值，则计数器将遍历 0、1 和 2。如果从 0 中减去 1，则得到 -1，在这种情况下无法使用。

我的建议是将其更改为类似

for i in [i for i in words if i in vector]:
    blabla

这会遍历 word 中的值，以防它也出现在向量中。如果你想比较一个单词在每个列表中的位置，你的方法当然效果更好。

【讨论】：